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kiruha [24]
3 years ago
15

Roll two dice what are the chances you roll atleast one six

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0
It is not very likely you would roll one six.
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Find a rectangular equation. X = 3tan t, Y = 2sec t, for in (−π /2 , π /2 )
anzhelika [568]

Answer:

Step-by-step explanation:

x= 3tan(t) \rightarrow tan(t) = \frac{x}{3} \rightarrow tan^2(t) = \frac{x^2}{9}

y= 2sec(t) \rightarrow sec(t) = \frac{y}{2} \rightarrow sec^2(t) = \frac{y^2}{4}

sec^2(t) -tan^2(t) =1

\frac{y^2}{4} -\frac{x^2}{9} =1

is the rectangular equation of the parameter functions.

also, it is a hyperbola. The condition -\pi/2 < t limit x from 0 to infinitive

7 0
3 years ago
Which line is parallel to y=4x-2?<br><br>(A) y=4x+3<br>(B) y=2x-4<br>(C) y=1/4x+1<br>(D) y=-1/4x+5
Gwar [14]
Parallel lines have the same slope but different y-intercepts. Which answer has the same slope as the one above? Hint: m is the slope (coefficient of x)
5 0
3 years ago
Alex and bob are playing 5 chess games. Alex is 3 times more likely to win than bob. What is the probability that both of them w
givi [52]

Answer:

12.2%

Step-by-step explanation:

Lets firstly find out the probabilities for Alex and Bob. We know that the prb that Alex wins is 3 times the prob for Bob, so:

P(A) = 3P(B)

And, as these values are probabilities they must sum 1:

P(A) + P(B) = 1

Replacing the first equation in the second:

3P(B) + P(B) = 1

4P(B) = 1

Dividing both sided by 4:

4P(B)/4 = 1/4

P(B) =1/4

So, the probability for Bob is 1/4. Then the probability for Alex is 3*1/4 = 3/4

Now we have to find the probability that both win at least two games. Lets think about the possible combination of cases. As they play 5 games and both have to win at least to there is a remaining game that cane variate, this is, can be won by Alex or Bob. So, we can have:

AABBB

AABBA

Where A is "Alex win" and B is "Bob win" (here we do not pay attention to the order).

Thus, we have to find the probability that Alex wins 3 games and Bob 2 games, and the probability that Alex wins 2 games and Bob 3 games. As the games are independent, i.e., the result of one games does not affect the followings we can just multiply the probabilities:

P(3A and 2B) = (3/4)*(3/4)*(3/4)*(1/4)*(1/4) = 0.42*0.06 = 0.026

P(2A and 3B) = (3/4)*(3/4)*(1/4)*(1/4)*(1/4) = 0.56*0.016 = 0.096

So,

P (at least 2) = P(3A and 2B) + P(2A and 3B) = 0.026 + 0.096 = 0.122 = 12.2%

7 0
3 years ago
I need 3 multiples of 10 that has 3 as one of the digits
d1i1m1o1n [39]
3 multiples of 10 that have 3 in them are 30, 300, and 3000
4 0
3 years ago
Read 2 more answers
Find the missing side of each triangle. leave your answers in simplest radical form
Marysya12 [62]
By the Pythagorean theorem
.. x = √((2√3)^2 -(√6)^2) = √(12 -6) = √6 . . . . cm

x = √6 cm
6 0
3 years ago
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