Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer:
Y=1/3x
Step-by-step explanation:
1) there is no y intercept as x=0 when y=0 so that rules out y=x-2
2) next, we will use the formula for slope to find the value of m
Y2-Y1/X2-X1
Where y2=-1
Y1=0
X2=-3
X1=0
So
-1-0/-3-0=-1/-3
Aka 1/3
So y=1/3x
Hope this helps!
Answer:
-1
Step-by-step explanation:
Answer:
C) 113 m^2
Step-by-step explanation:
diameter/2 =radius = 12/2 = 6
area = 6^2(3.14) = 6x6x3.14 = 113 m^2