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cupoosta [38]
3 years ago
6

5. Find the point P along the directed line segment from X(-3, 3) to Y(6,-3) that divides

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
Consider point P(x,y) such that P, X and Y are collinear,

As vectors

XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)

Similarly,

PY = (6-x, -3-y)

But XP= 2^PY

[x+3, y-3] = [2(6-x), 2(-3-y)]

Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:

x+3 = 12 - 2x

x = 3

y-3 = -6-2y

y = -1

Therefore, P(3,-1)

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<h2>Q: 25-(3x+5)=2(x+8)+x</h2>
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3 years ago
How do i solve 51/2x-7=62
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51/2x-7=62

  1. Multiply both sides by 2x-7

\frac{51}{2x-7} ×(2x-7) = 62(2x-7)

    2. Switch sides

62(2x-7) = 51

     3. Divide each side by 62

\frac{62(2x-7)}{62} = \frac{51}{62}

     4. Simplify

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