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marissa [1.9K]
4 years ago
14

What are the coordinates of vertex F" of F"G"H"?

Mathematics
2 answers:
anzhelika [568]4 years ago
5 0

Answer:(4,-1.5)

Step-by-step explanation:

You’d be adding 5,-0.5 to the respective coordinates. Point F’ is located at -1,-1 so you’d be adding 5 to -1 for the x coordinate and -0.5 to -1 for the y coordinate.

devlian [24]4 years ago
3 0

Answer:

A

Step-by-step explanation:

just took the test

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Imagine that you are filling treat bags with jellybeans. You have 3 3/8 cups of jellybeans, and each treat bag will contain 1/4
Temka [501]

Answer:

13.5

Step-by-step explanation:

3 3/8 / 1/4 = 27/2= 13 1/2= 13.5

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3 0
3 years ago
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How many gloves did mrs edwards knit
marta [7]

Answer:

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5 0
3 years ago
HELP!!! There is a photo please quickly!!
Nostrana [21]

Answer:

∆y = 9

∆x = 6

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Step-by-step explanation:

7 0
1 year ago
I need help answering this question
Advocard [28]

Answer:

x = 17

Step-by-step explanation:

Since line m is parallel to line n, therefore:

(6x + 5) + (5x - 12) = 180 (consecutive interior angles are supplementary)

Solve for x

6x + 5 + 5x - 12 = 180

Add like terms

11x - 7 = 180

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8 0
3 years ago
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:

<span>The interquartile range is the difference between the third and the first quartiles.

The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5

The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
6 0
3 years ago
Read 2 more answers
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