Find the value of x (3x-9) (x + 7)

X^3+2/3x^4-1/2x^2 integral

Irina-Kira [14]

$\frac{2 {x}^{5} }{15} + \frac{ {x}^{4} }{4} - \frac{ {x}^{3} }{6} + c$

simplified form =

$\frac{ {x}^{3}(8 {x}^{2} + 15x - 10) }{60} + c$

5 0

2 years ago

ASAP! Students just finished taking test and these are the scores: 75, 80, 62, 98, 90, 86, 55, 86, 92, 66. What is the range of

harkovskaia [24]

The answer would be A.83 if I’m not mistaken, sorry if I’m no help

4 0

2 years ago

Help please asap. best answer gets brainliest.

schepotkina [342]

Answer:

Step-by-step explanation:

4 is coefficient

x is variable

12 is constant

5 0

2 years ago

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Help this is the last question to a test

goblinko [34]

You’re a Horrible Person
Solutions are given in alphabetical order (k, x, y, z)

[(1, 0, 0, 1), (1, 0, 1, 0), (1, 1, 0, 0), (2, 0, 1, 1), (2, 1, 0, 1), (2, 1, 1, 0), (3, 1, 1, 1), (8, 0, 0, 2), (8, 0, 2, 0), (8, 2, 0, 0), (9, 0, 1, 2), (9, 0, 2, 1), (9, 1, 0, 2), (9, 1, 2, 0), (9, 2, 0, 1), (9, 2, 1, 0), (10, 1, 1, 2), (10, 1, 2, 1), (10, 2, 1, 1), (16, 0, 2, 2), (16, 2, 0, 2), (16, 2, 2, 0), (17, 1, 2, 2), (17, 2, 1, 2), (17, 2, 2, 1), (24, 2, 2, 2), (27, 0, 0, 3), (27, 0, 3, 0), (27, 3, 0, 0), (28, 0, 1, 3), (28, 0, 3, 1), (28, 1, 0, 3), (28, 1, 3, 0), (28, 3, 0, 1), (28, 3, 1, 0), (29, 1, 1, 3), (29, 1, 3, 1), (29, 3, 1, 1), (35, 0, 2, 3), (35, 0, 3, 2), (35, 2, 0, 3), (35, 2, 3, 0), (35, 3, 0, 2), (35, 3, 2, 0), (36, 1, 2, 3), (36, 1, 3, 2), (36, 2, 1, 3), (36, 2, 3, 1), (36, 3, 1, 2), (36, 3, 2, 1), (43, 2, 2, 3), (43, 2, 3, 2), (43, 3, 2, 2), (54, 0, 3, 3), (54, 3, 0, 3), (54, 3, 3, 0), (55, 1, 3, 3), (55, 3, 1, 3), (55, 3, 3, 1), (62, 2, 3, 3), (62, 3, 2, 3), (62, 3, 3, 2), (64, 0, 0, 4), (64, 0, 4, 0), (64, 4, 0, 0), (65, 0, 1, 4), (65, 0, 4, 1), (65, 1, 0, 4), (65, 1, 4, 0), (65, 4, 0, 1), (65, 4, 1, 0), (66, 1, 1, 4), (66, 1, 4, 1), (66, 4, 1, 1), (72, 0, 2, 4), (72, 0, 4, 2), (72, 2, 0, 4), (72, 2, 4, 0), (72, 4, 0, 2), (72, 4, 2, 0), (73, 1, 2, 4), (73, 1, 4, 2), (73, 2, 1, 4), (73, 2, 4, 1), (73, 4, 1, 2), (73, 4, 2, 1), (80, 2, 2, 4), (80, 2, 4, 2), (80, 4, 2, 2), (81, 3, 3, 3), (91, 0, 3, 4), (91, 0, 4, 3), (91, 3, 0, 4), (91, 3, 4, 0), (91, 4, 0, 3), (91, 4, 3, 0), (92, 1, 3, 4), (92, 1, 4, 3), (92, 3, 1, 4), (92, 3, 4, 1), (92, 4, 1, 3), (92, 4, 3, 1), (99, 2, 3, 4), (99, 2, 4, 3), (99, 3, 2, 4), (99, 3, 4, 2), (99, 4, 2, 3), (99, 4, 3, 2)]

3 0

3 years ago

A conjecture and the two-column proof used to prove the conjecture are shown.

aliina [53]

Answer: the statements and resons, from the given bench, that fill in the blank are shown in italic and bold in this table:

Statement Reason

1. K is the midpoint of segment JL Given

2. segment JK ≅ segment KL Definition of midpoint

3. L is the midpoint of segment KM Given

4. segment KL ≅ segment LM Definition of midpoint

5. segment JK ≅ segment LM Transitive Property of

Congruence

Explanation:

1. First blank: you must indicate the reason of the statement "segment JK ≅ segment KL". Since you it is given that K is the midpoint of segment JL, the statement follows from the very Definition of midpoint.

2. Second blank: you must add a given statement. The other given statement is segment KL ≅ segment LM .

3. Third blank: you must indicate the statement that corresponds to the definition of midpoint. That is segment KL ≅ segment LM .

4. Fourth and fith blanks: you must indicate the statement and reason necessary to conclude with the proof. Since, you have already proved that segment JK ≅ segment KL and segment KL ≅ segment LM it is by the transitive property of congruence that segment JK ≅ segment LM.

5 0

3 years ago

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