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3 years ago

TIME REMAININ

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

6 0

Answer:

Infinitely many solutions.

Step-by-step explanation:

y = -6x + 2

Add 6x to both sides

6x + y = 2

-12x - 2y = -4

Divide each term by -2

6x + y = 2

Since both equations are actually exactly the same, this linear system will have infinitely many solutions.

Hope this helps!

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Please help me with this question

Alex17521 [72]

Answer:

The answer is C.

Step-by-step explanation:

5*6=30

5 0

3 years ago

Read 2 more answers

A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price

Nataliya [291]

Answer:

a) $P=3(120-s)+200$

b) $215 \leq P \leq 290$

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

$s$ number of seats, if w analyze the info given the number of seats after increase the price is given by $120-s$ .

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

$P-200=3(120-s)$

So then our linear equation is given by:

$P=3(120-s)+200$

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

$P_L=3(120-90)+200=290$

$P_U=3(120-115)+200=215$

So the corresponding range of ticket prices is:

$215 \leq P \leq 290$

4 0

3 years ago

Please help 15 points and will give brainliest

Andrej [43]

Answer:

Think it is A as 4x20=80.

8 0

3 years ago

Pleaseeeeee help !!

umka21 [38]

$A.\\-vp+40 < 95\qquad\text{subtract 40 from both sides}\\\\-vp < 55\qquad\text{change the signs}\\\\vp > -55\qquad\text{divide both sides by p}\\\\If\ p > 0\ then\ v>-\dfrac{55}{p}.\\\\If\ p < 0\ then\ v < -\dfrac{55}{p}$

$B>\\8w-3r=45\qquad\text{subtract 8 from both sides}\\\\-3r=-8w+45\qquad\text{change the signs}\\\\3r=8w-45\qquad\text{divie both sides by 3}\\\\r=\dfrac{8w-45}{3}$