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strojnjashka [21]
3 years ago
13

On the coordinate plane, the x-axis and y-axis are to each other.

Mathematics
2 answers:
andriy [413]3 years ago
8 0

Answer:

True

Step-by-step explanation:

Technically:

The y-axis is the one that stands up vertically and the x-axis is the one that lays down horizontally.

Hope this helps.

pishuonlain [190]3 years ago
7 0

Answer:

yes that's perfectly true

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(1) If DF = FB, then point F is called the _____ and segments DF and FB are _____.
Vesnalui [34]

Answer:

(1) C

(2) C

(3) 4

(4) False

Step-by-step explanation:

(1) If DF = FB, then point F is called the midpoint and segments DF and FB are congruent.

(2) If ray FA bisects angle EFB, then angles EFA and AFB are congruent.  If measure of angle EFA = 47 degrees, the measure of angle EFB = 47 degrees.

(3) If  DF = x+2,  FB = 2x+1 and DB = 15, then

DF + FB = DB

x+2+2x+1=15

3x+3=15

3x=15-3

3x=12

x=4

(4) If x=4, then

DF=4+2=6

FB=2·4+1=9

Since DF is not congruent to FB, F is not a midpoint. False

8 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP(25 points)
miskamm [114]

Answer: I hope it helps :)

  • x=6 , y=6√3
  • x =23√3 , y=23
  • u =12 , v= 6
  • a =18√2 , b =18
  • x = 13 , y= 13

Step-by-step explanation:

1.

Hypotenuse =x\\Opposite =y \\Adjacent =6\\\alpha = 6\\Let's\: find\: the \:hypotenuse\: first\\Using SOHCAHTOA\\Cos \alpha = \frac{adj}{hyp} \\Cos 60 = \frac{6}{x} \\\frac{1}{2} =\frac{6}{x} \\Cross\:Multiply\\x = 12\\Let's\: find\: y\\Hyp^2=opp^2+adj^2\\12^2=y^2+6^2\\144=y^2+36\\144-36=y^2\\108=y^2\\\sqrt{108} =\sqrt{y^2} \\y=6\sqrt{3}

2.

Opposite =x\\Hypotenuse = 46\\Adjacent =y \\\alpha =60\\Using \: SOHCAHTOA\\Sin \alpha =\frac{opp}{adj} \\Sin 60=\frac{x}{46}\\\\\frac{\sqrt{3} }{2} =\frac{x}{46}  \\2x=46\sqrt{3} \\x = \frac{46\sqrt{3} }{2} \\x =23\sqrt{3} \\\\Hyp^2=opp^2+adj^2\\46^2=(23\sqrt{3} )^2+y^2\\2116=1587+y^2\\2116-1587=y^2\\529=y^2\\\sqrt{529} =\sqrt{y^2} \\y = 23

3.

Hypotenuse = u\\Opposite =6\sqrt{3} \\Adjacent = v\\\alpha =60\\Sin\: 60 = \frac{6\sqrt{3} }{u} \\\frac{\sqrt{3} }{2} =\frac{6\sqrt{3} }{u} \\12\sqrt{3} =u\sqrt{3} \\\\\frac{12\sqrt{3} }{\sqrt{3} } =\frac{u\sqrt{3} }{\sqrt{3} } \\u = 12\\Hyp^2=opp^2+adj^2\\12^2= (6\sqrt{3} )^2+v^2\\144=108+v^2\\144-108=v^2\\36 = v^2\\\sqrt{36} =\sqrt{v^2} \\\\v =6

4.

Hypotenuse = a\\Opposite =18 \\Adjacent = b\\\alpha =45\\Tan \alpha = opp/adj\\Tan \:45 =18/b\\1=\frac{18}{b}\\ b = 18\\\\Hyp^2=Opp^2+Adj^2\\a^2 = 18^2+18^2\\a^2=324+324\\a^2=648\\\sqrt{hyp^2} =\sqrt{648}\\ \\a =18\sqrt{2}

5.

Hypotenuse = 13\sqrt{2}\\ Opposite =x\\Adjacent = y\\\alpha =45\\Sin\:\alpha = opp/hyp\\Sin 45=x/13\sqrt{2}\\ \\\frac{\sqrt{2} }{2} =\frac{x}{13\sqrt{2} } \\2x=26\\2x/2=26/2\\\\x = 13\\\\Hyp^2=opp^2+adj^2\\(13\sqrt{2})^2=13^2+y^2\\ 338=169+y^2\\338-169=y^2\\169=y^2\\\sqrt{169} =\sqrt{y^2} \\13 = y

7 0
3 years ago
1. -3x+32= -x-12 2. 8x+16=x+9 3. 3x + 2 = 2x -55 I need all the steps to all three of those questions
Oksanka [162]

Answer:

Step-by-step explanation:

1. - 3x + 32 = - x - 12

-3x + x = - 12 - 32

-2x = - 44

x = 44/2 = 22

2. 8x + 16 = x + 9

8x - x = 9 - 16

7x = - 7

x = - 7/7

= - 1

3. 3x + 2 = 2x - 55

3x - 2x = - 55 - 2

x = - 57

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3 years ago
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The following formula relates three quantities: Force (F), mass (m), and acceleration (a).
Pie

(a) F=ma       

      a=F/m

 (b) a=25/10

      a=2.5

    2.5*10=25

(c)  m= 25/5

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3 years ago
Laura rents a movie for a flat fee of $2.00 plus an additional $0.50 for each night she keeps the movie. Choose the cost functio
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B. c(x) = 2.00 + 0.50x
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