Mrs Li's classroom is 34 feet wide and 42 feet long. Objects in classroom Mrs. Li's Desk, Fish Tank, Math Center, or Reading Cen
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The correct answers are:
- The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true.
- The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false.
Further explanation:
Given equations are:
2x-y = -5
x+3y = 22
We have to check whether the given statements are true or not. In order to find that we have to put the points in the equations
Putting the point in 2x-y = -5
Putting the point in x+3y=22
The point satisfies the first equation but doesn't satisfy the second. So,
1. The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true.
This statement is true as the point satisfies the first equation
2. The ordered pair (7, 19) is a solution to the second equation because it makes the second equation true.
This Statement is false.
3. The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false.
This statement is true.
4. The ordered pair (7, 19) is a solution to the system because it makes both equations true.
This statement is false as the ordered pair doesn't satisfy both equations.
Keywords: Solution of system of equations, linear equations
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Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.
We are to find the probability of selecting 1 red apple and 2 yellow apples.
Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.
Then, we have
Therefore, the probability of event A is given by
Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.
Answer:
Step-by-step explanation:
Given expression:
Replace 900 with 30² :
(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).
Simplify:
(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).