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ASHA 777 [7]
3 years ago
11

Please Help!I need this for an important TestYou will be deeply appreciated​

Mathematics
2 answers:
tamaranim1 [39]3 years ago
8 0
A will to the fifth power.
Vladimir [108]3 years ago
5 0
A Because the equation at the top is 4^6 and b and c are the same answer
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What is​ logic? Briefly explain how logic can be useful.
Andreyy89

Logic is a deceptive argument. It is useful in marketing products and creating advertisements

I think because logic is idea used from brain.

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3 years ago
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What is 2.24 rounded to the nearest tenth?
quester [9]
One tenth is 0.1.  Therefore, the answer has to be 2.x.  Since 4 is less than 5, the 2 remains the same.  The answer is 2.2.  
3 0
2 years ago
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Start at 1000 create a pattern that subtracts 8 from each number. Stop when you have 5 numbers
kifflom [539]
Well, you do 1000-8 then put your answer down.
Answer is 992
Then do 992-8
Answer is 984
Then do 984 - 8
Answer is 976
Then do 976-8
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Then do 968 -8
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Your final answers are 992,984,976,968,960.
7 0
3 years ago
Ten college students were randomly selected. Their grade point averages​ (GPAs) when they entered the program were between 3.5 a
solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

\hat y=\alpha +\hat \beta x

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope (\hat \beta ) is:

Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

\hat Y=3.584756+0.090953 X

The summary of the regression analysis is:

Predictor          Coefficient             SE             t-stat            p-value

Constant             3.584756          0.078183       45.85075      5.66 x 10⁻¹¹

Entering GPA   0.090953          0.022162        4.103932       0.003419

The regression coefficient and standard error are:

\hat \beta = 0.090953\\SE (\hat \beta)=0.022162

The critical value of <em>t</em>  for 95% confidence level and 8 degrees of freedom is:

t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306

Compute the 95% confidence interval for (\hat \beta ) as follows:

CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0
2 years ago
Can some one please help me
Nady [450]
40 = 1 x 2 x 2 x 2 x 5
8 0
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