2 years ago

Students at a middle school are divided into 6th, 7th, and 8th grades. A random sample of 15 students from each grade is chosen.

Mathematics

1 answer:

Julli [10]2 years ago

4 0

Answer:

B. Stratified random sample is the correct answer

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Verify ∠A ≅ ∠D and ∠B ≅ ∠E by translation

Step-by-step explanation:

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2 years ago

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pantera1 [17]

<h3>Answer: Choice D) </h3>

Work Shown:

$(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\$

We must require that $x \ne -12$ and $x \ne 3$ to avoid having 0 in the denominator. This is why choice D is the answer.

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2 years ago

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