Answer:
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<em>The team must win 2 games to have a win : loss ratio o 2.</em>
Step-by-step explanation:
- <u>Ratio win : loss, r</u>:
r = total wins / total losses
Call n the number of new wins:
Tw =number of wins until so far + number of new win = 6 + n
Tl = number of losses so far + number of new losses = 4 + 0 = 4
r = 2 ⇒ Tw / Tl = (6 + n) / 4 = 2
Solve for n:
- (6 + n ) = 4 × 2
- 6 + n = 8
- n = 8 - 6
- n = 2
Hence,<em> the team must win 6 more games.</em>
- <u>Verification</u>: (6 + 2 ) / 4 = 8 / 4 = 2, which is the target ratio.
16 - 5(3t - 4) = 8(-2t + 11) <em>use distributive property</em>: <em>a(b + c) = ab + ac</em>
16 - (5)(3t) - (5)(-4) = (8)(-2t) + (8)(11)
16 - 15t + 20 = -16t + 88
36 - 15t = -16t + 88 <em>subtract 36 from both sides</em>
-15t = -16t + 52 <em>add 16t to both sides</em>
t = 52
Answer:
maximum value of y = 3
Step-by-step explanation:
line Starts at -4 , 0 & turns at - 1 , 3
Slope = (3 - 0)/(-1 -(-4)) = 3/3 = 1
y = x + c
=> 0 = - 4 + c => c = 4
=> y = x + 4
line after turning crosses the y-axis at (0, 2) and the x-axis at (2, 0)
slope of this line : (0-2)/(2-0) = -1
y = - x + c
2 = 0 + c => c = 2
=> y = - x + 2
=> y = 2 - x
Values Drawn
x y
-4 0
-3 1
-2 2
-1 3
0 2
1 1
2 0
The answer is no question for you lol
Answer:
alicia is right
Step-by-step explanation:
if u divide 6 by 2 that would be 3 and then add 5 = 8. If you do the same with the next equation it still = 8 bc pemdas so divide first
