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4 years ago

Travis is temporarily not working while his office is being remodeled. He

1 answer:

8 0

I believe the answer is B.
Because he can not afford to to pay them at the moment but he will be able to pay them when they are done and he gets to go back to work

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Dan buys a car for £2200.

KatRina [158]

Answer:

The worth of the car after 6 years is £2,134.82

Step-by-step explanation:

The amount at which Dan buys the car, PV = £2200

The rate at which the car depreciates, r = -0.5%

The car's worth, 'FV', in 6 years is given as follows;

$FV = PV \cdot \left ( 1 + \dfrac{r}{100} \right )^n$

Where;

r = The depreciation rate (negative) = -0.5%

FV = The future value of the asset

PV = The present value pf the asset = £2200

n = The number of years (depreciating) = 6

By plugging in the values, we get;

$FV = 2200 \times \left ( 1 + \dfrac{-0.5}{100} \right )^6 \approx 2,134.82$

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))

8 0

3 years ago

Terry invested money in a biotech stock whose growth is modeled by the function f(x) = 0.01(2)x, where x represents number of da

strojnjashka [21]

Answer:

The average rate of change is 1.275

Step-by-step explanation:

The average rate of change of f(x) from x=a to x=b is given by:

$\frac{f(b)-f(a)}{b-a}$

The money Terry invested is modeled by the function $f(x)=0.01(2)^x$ where x represents number of days.

The average rate of change from day 2 to day 10 is given by:

$\frac{f(10)-f(2)}{10-2}$

$f(10)=0.01(2)^{10}=10.24$

$f(2)=0.01(2)^{2}=0.04$

The average rate of change becomes:

$\frac{10.24-0.04}{8}$

$=\frac{10.2}{8}=1.275$

3 0

3 years ago

Read 2 more answers

How much does a chicken cost and duck?

Firdavs [7]

Answer:

Chicken is $8

Duck is $5

Step-by-step explanation:

Step 1: Let $x$ represent the cost of chickens and let $y$ represent the cost ducks. Since we have two unknowns, we need two equations to find them.

Step 2: The total cost of chickens Michael sold last month can be shown as $50x$ , and the total cost of ducks he sold last month can beshown as $30y$ Since these together add up to 550, we get these equations:

$50x+30y = 550$

We are also given that this month, Michael sold 44 chickens, and 36start text, 36 ducks, $532. This equaion can be expressed as:

$44x+36y=532$

Now that we have a system of the two equations, we can now go ahead and solve the two equations.

Step 3: We can now solve the system of equations by using the elimination method. Manipulate the equations so one of the variables has the same coefficients but with opposite signs.

$-6*50x+(-6)*30y\\=-300x-180y\\=-6*550\\=-3300$ $5*44x+5*36y\\=220x+180y\\=5*532\\=2660$

Now eliminate $y$

$-300x-180y=-3300\\+220x+180y=2660\\=-80x-0=-640$

When we solve the resulting equation, we obtain that $x=8$ . Then, we can substitute this into one of the original equations and solve for $y$ to obtain $y=5$ .