Ok so domain is all allowed numbers
look at deonomenator and don't allow any numbers that will make it zero
none
that means
domain=all real numbers
vertex
in form
y=a(x-h)^2+k
(h,k)=vertex
we have
y=-2(x+3)^2-1
h=-3
k=-1
vertex=(-3,-1)
range
the vertex opens down so max is y=-1
y≤-1
domain is all real
vertex is (-3,-1)
y≤-1
C
Answer:
1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻
Step-by-step explanation:
1. Let b be the number and B be the set, so mathematically, it is written as
b ∈ B.
2. Let a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write
∀ a ∈ N; 2a ∈ Z
3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.
Since each set is a subset of the latter set, we write
N ⊂ Z ⊂ Q ⊂ R .
4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write
J ≤ J⁻¹ : J ∈ Z⁻
Prime Factors of 60: 2,3, and 5
Prime Factors of 140: 2,5 and 7
All mental math no work needed.
45.908 / 300.6 = 0.152721224
:)
Okay first set up the equation
x
--- -2 = 5.5
-3
add over the 2
x
--- = 7.5
-3
now you need to multiply the denominator by the answer
(-3)(7.5) = x
-22.5 = x
