You know a1.
So find a2, a3, and so on until a7.
a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
Biggest is all nine's
smallest is 1 then zeroes
greatest
999999
smallest
10000
Answer:
125/12
Step-by-step explanation:
1st problem-no
2nd problem-yes
3rd problem-yes
4th problem-no
I believe it would be the second option....