Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is

Using this formula, we get


and


Now, area of the quadrilateral is



Therefore, the area of the quadrilateral is 34 cm².
Total area of zone and playground, (x+50)(x+30);
and this whole area is twice the area of the playground, consistent with description.
highlight_green%28%28x%2B50%29%28x%2B30%29=2%2A50%2A30%29;
Solve for x.
Answer:
x=-2
Step-by-step explanation:
14-(x+5)=3(x+9)-10
14-x-5=3x+27-10
14-5-x=3x+17
+x +x
9=4x+17
-17 -17
4x=-8
4x/4=-8/4
x=-2
Answer: J
Explanation: J is equivalent to $640.65
hope that helps if you have any questions let me know and if you could mark this as brainliest i would really appreciate it!!
3 x 2 and 1/3? The answer is 7.