The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² = 
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon = 
Therefore, the pool can hold 65.84 ft³ of water
We will be using the formula in looking for the volume of the cylinder which is
V = πr²h
where:
r = radius
h = height
V = volume
but in the problem V and r have values already:
r = 8
V = 4019.2
plug this in the volume equation:
V = πr²h
= 4019.2 = π* 8² * h
= 4019.2 = 64πh
= 4019.2 / 64π = h
so the answer is: h = 4019.2 /201.06193
= 19.99 is the height of the cylinder.
Answer:
yes
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
intercept is -4 and slope is rise over run which is 3/1 = 3
put into slope intercept form to achieve answer D
Question 4 is Choice A
Question 5 is Choice B
Question 6 is Choice C
Question 7 is Choice B
These are relatively simple it’s just understanding the relations of x and y values :)
