Answer:
Given statement is TRUE.
Step-by-step explanation:
Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.
We know that corresponding angles formed by transversal line are congruent.
Hence ∠JKL = ∠ MLK ...(i)
Now consider triangles JKL and MLK
JK = LM {Given}
∠JKL = ∠ MLK { Using (i) }
KL = KL {common sides}
Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.
Hence given statement is TRUE.
The problem is asking how much each person will need to pay. Simplifying the problem into an equation with variables (an algorithm) will greatly help you solve it:
S = Sales Tax = $ 7.18 per any purchase
A = Admission Ticket = $ 22.50 entry price for one person (no tax applied)
F = Food = $ 35.50 purchases for two people
We know the cost for one person was: (22.50) + [(35.50/2) + 7.18] =
$ 47.43 per person. Now we can check each method and see which one is the correct algorithm:
Method A)
[2A + (F + 2S)] / 2 = [ (2)(22.50) + [35.50 + (2)(7.18)] ]/ 2 = $47.43
Method A is the correct answer
Method B)
[(2A + (1/2)F + 2S) /2 = [(2)(22.50) + 35.50(1/2) + (2)7.18] / 2 = $38.55
Wrong answer. This method is incorrect because the tax for both tickets bought are not being used in the equation.
Method C)
[(A + F) / 2 ]+ S = [(22.50 + 35.50) / 2 ] + 7.18 = $35.93
Wrong answer. Incorrect Method. The food cost is being reduced to the cost of one person but admission price is set for two people.
Let's solve the equation:
9x+27 = 9(x+2)+9 ← Distribute 9 to the x and 2
9x+27 = 9x+18+9 ← Combine like terms
9x+27 = 9x + 27 ← Subtract 27 from both sides
9x = 9x
Infinitely many solutions would be correct because no matter what x is, it will always equal each other the both sides of the equation because it is 9 times x on both sides.
Answer:
1) decay
2) growth
3) growth
Step-by-step explanation:
A generic exponential function can be written as:
f(x) = A*(r)^x
Where:
A is the initial amount of something.
r is the rate of growth.
x is the variable, usually, represents time.
if r > 1, we have an exponential growth.
if r < 1, we have an exponential decay.
1) f(x) = (3/4)^x
in this case we have:
A = 1
r = (3/4) = 0.75
Clearly, r < 1.
Then this is an exponential decay.
2) f(x) = (1/6)*4^x
In this case we have:
A = (1/6)
r = 4
Here we have r > 1.
Then this is an exponential growth.
3) f(x) = (1/4)*(5/2)^x
in this case we have:
A = 1/4
r = 5/2 = 2.5
here we have r > 1, then this is an exponential growth.
Do you know the subject that the problem is about ?
