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11Alexandr11 [23.1K]
3 years ago
13

Plzzzzzzzzz help meeeeeeeeeeeeee

Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer:

<em>Solution; x = - 2, x = 5</em>

Step-by-step explanation:

We are given the following equation 2x^2 + 2x + 12 = 3x^2 - x + 2;

2x^2 + 2x + 12 = 3x^2 - x + 2 ⇒ Subtract 2 from either side,

2x^2 + 2x + 10 = 3x^2 - x ⇒ Add x on either side,

2x^2 + 2x + 10 = 3x^2 ⇒ Subtract 3x^2 on either side, simplifying result,

- x^2 + 3x + 10 = 0 ⇒ Factor out common term - 1,

- ( x^2 - 3x - 10 ) = 0 ⇒ Break expression into groups,

- ( x^2 + 2x ) + ( - 5x - 10 ) = 0⇒ Factor x from x^2 + 2x , and - 5 from - 5x - 10,

- ( x( x + 2 ) ) - 5( x + 2 ) = 0 ⇒ Factor out common term x + 2,

- ( x + 2 )( x - 5 ) = 0 ⇒ Apply Zero Factor Principle,

x + 2 = 0, and x - 5 = 0 ⇒ Simplify,

<em>Solution; x = - 2, x = 5</em>

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Step-by-step explanation:

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Solving by elimination <br> 5x+2y= -3<br> 3x+3y=9<br> please help me solve x and y
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2) -9x/-9=27/-9 ⇒ x=-3 

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Answer: (-3,6)

Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.

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