50 POINTS find the length of ab plz help me
2 answers:
Answer:
about 9.4 units
Step-by-step explanation:
Distance formula:
√(x1 - x2)² + (y2 - y1)²
Coordinates:
A (4, 2)
B (9, 10)
Let's make 9 = x1
Let's make 4 = x2
Let's make 10 = y1
Let's make 2 = y2
Substitute into the distance formula:
√(x1 - x2)² + (y2 - y1)²
√(9 - 4)² + (2 - 10)²
Solve:
√(9 - 4)² + (2 - 10)²
√(5)² + (-8)²
√25 + 64
√89
≈ 9.4
Therefore, the length of AB is approximately 9.4 units.
Answer:
About 9.4 units
Step-by-step explanation:
To find the distance between two points
d = sqrt(( y2-y1) ^2 + (x2-x1) ^2) where (x1,y1) and (x2,y2) are the points
= sqrt(( 10-2)) ^2 + (9-4) ^2)
= sqrt((8) ^2 + (5) ^2)
= sqrt(64+ 25)
= sqrt(89)
=9.433981132
About 9.4 units
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