Find the truth table for the circuit shown. Explain the working principle for all the inputs, briefly. Explain why D1 is used in
the network.
1 answer:
Answer:
see below for the truth table
Explanation:
<u>Truth Table</u>
As we will see from the description of operation, any input low causes the output to be high. This is the logic of a NAND gate. The truth table is attached.
<u>Working Principle</u>
Pulling any of A, B, or C low will saturate transistor Q1, depriving Q2 of any base current, cutting it off. Then Q5 is also deprived of base current and is cut off. Meanwhile, the current through R2 supplies base current to Q4, allowing it to pull the output high.
If all of A, B, and C are high (or open), base current is supplied to Q2 through the base-collector junction of Q1. Then Q2 saturates, supplying base current to Q3. Diode D1 ensures that the voltage across Q2 will be insufficient to supply any base current to Q4, so it stays cut off.
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Answer:
Explanation:
According to the Coulomb's law, the magnitude of the electrostatic force between two static point charges and
, separated by a distance
, is given by
where k is the Coulomb's constant.
Initially,
The negative sign is taken with force F because the force is attractive.
Therefore, the initial electrostatic force between the charges is given by
Now, the objects are then brought into contact, so the net charge is shared equally, and then they are returned to their initial positions.
The force is now repulsive, therefore,
The new charges on the two objects are
The new force is given by
Using (1),
Using (1),
When ,
When ,
Since,
Therefore,
Answer:
the amplitude of the subsequent oscillations is 0.11 m
the period of the subsequent oscillations is 1.94 s
Explanation:
given Information:
the mass of air-track glider, = 750 g = 0.75 kg
spring constant, k = 13.0 N/m
the mass of glider, = 200 g = 0.2 kg
the speed of glider, = 170 cm/s = 1.7 m/s
the amplitude of the subsequent oscillations is A = 0.11 m
according to mechanical enery equation, we have
where
A is the amplitude and is the final speed.
to find , we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.
= 0, thus
(0.75+0.2) = (0.75)(0)+(0.2)(1.7)
0.95 = 0.34
= 0.36 m/s
Now we can calculate the amplitude
A = 0.11 m
the period of the subsequent oscillations is T = 1.94 s
the equation for period is
T = 2π
T = 2π
T = 1.94 s