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Sedaia [141]
3 years ago
8

Describe three events that you cannot explain. About energy and matter

Physics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

A teacher giving homework on fridays

A teacher giving tests on fridays

A teacher holding you back after class on fridays

Explanation:

because i luv friday

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if a freely falling object were somehow equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s/
Pie

Answer: The speed reading would increase each second by 20m/s

Explanation:

Acceleration is the change in velocity per unit change in time.

Acceleration = velocity/time

∆v = a∆t

Given a = g = 20m/s/s (acceleration due to gravity)

∆t = 1 sec

∆v = 20m/s/s × 1s

∆v = 20m/s

Therefore, the speed reading would increase each second by 20m/s

3 0
4 years ago
What is string theory? Need answer in own word​
Makovka662 [10]

Answer:

When point particals are replaced by string like particals

Explanation:

4 0
3 years ago
A uniform meter stick is hung at its center from a thin wire. It is twisted and oscillates with a period of 5 s. The meter stick
rewona [7]

Answer:

The new time period is  T_2 =  3.8 \  s

Explanation:

From the question we are told that

  The period of oscillation is  T =  5 \ s

   The  new  length is  l_2  =  0.76  \ m

Let assume the original length was l_1 = 1 m

Generally the time period is mathematically represented as

         T  =  2 \pi   \sqrt{ \frac{ I }{ mgh } }

Now  I is the moment of inertia of the stick which is mathematically represented as

           I  =  \frac{m * l^2 }{12 }

So

        T  =  2 \pi   \sqrt{ \frac{  m * l^2 }{12 *   mgh } }

Looking at the above equation we see that

        T  \ \ \  \alpha  \ \ \  l

=>    \frac{ T_2 }{T_1}  =  \frac{l_2}{l_1}

=>    \frac{ T_2}{5} =  \frac{0.76}{1}

=>     T_2 =  3.8 \  s

3 0
4 years ago
What is the change in internal energy (deltaE ) of a system when it loses 76.0 J of heat while the surroundings perform 29.0 J o
lisabon 2012 [21]

Answer:

-47 J

Explanation:

Given that,

Heat loss = -76 J (negative for loss)

Work done by the surroundings = -29 J

We need to find the change in internal energy of a system.

The first law of thermodynamics is given by :

\Delta U=Q-W

W is work done by the system

Putting all the values,

\Delta U=(-76)-(-29)\\\\=-47\ J

Hence, the change in internal energy is -47 J.

3 0
3 years ago
Homework B5
nydimaria [60]

Answer:

I hope this helps a little bit.

7 0
3 years ago
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