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rusak2 [61]
3 years ago
9

Are there concepts/processes to strictly follow in writing radicals as expressions with rational exponents?

Mathematics
1 answer:
Eva8 [605]3 years ago
5 0

Answer:

The concept or process is x^{\frac{m}{n}}=(\sqrt[n]{x})^m.

Step-by-step explanation:

Consider the provided information.

The following property can be used to rewrite each radical as an exponent.

The numerator tells the power of the resulting rational exponent, and the denominator of the rational exponents tells the root of that number.

x^{\frac{m}{n}}=(\sqrt[n]{x})^m

For example:

(27)^{\frac{2}{3}}=(\sqrt[3]{27})^2

(27)^{\frac{2}{3}}=(3)^2

(27)^{\frac{2}{3}}=9

Hence, the concept or process is x^{\frac{m}{n}}=(\sqrt[n]{x})^m.

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AleksAgata [21]
It rounds to 50 because the back number is below the 5
8 0
3 years ago
Jason with 120 and is going 10 pounds each month Gerardo weighs 150 pounds and is having 4 pounds each month . Write an equation
pshichka [43]

Answer:

5 months

Step-by-step explanation:

Jason's original weight = 120 pounds

Let the no. of months be m

If he gains 10 pounds in each moth , then his weight in m months will be = 10m

His total weight will be= 120+10m  -----(1)

Gerardo's original weight = 150 pounds

If he gains 4 pounds in each month , then his weight in m months will me =4m

His total weight will be = 150+4m-----(2)

<u>Equating (1) ans(2)</u>

120+10m=150+4m

=>10m-4m=150-120

=>6m=30

=>m=\frac{30}{6}

<u>=>m=5</u>

It will take 5 months for Jason to weigh the same as Gerardo

5 0
3 years ago
Need help with geometric sequences <br> 30 points
NeTakaya

Answer:

a_{n} = 6(5)^{n-1}

Step-by-step explanation:

The n th term of a geometric sequence is

a_{n} = a(r)^{n-1}

where a is the first term and r the common ratio

Here a = 6 and r = 30 ÷ 6 = 5, thus

a_{n} = 6(5)^{n-1}

8 0
3 years ago
A building is known to be 192 feet tall. A ball is dropped from the top of the building. In how many seconds will the ball hit t
Archy [21]

Answer:

  • h = 0 when the ball hits the ground
  • about 3.464 seconds

Step-by-step explanation:

The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.

__

Using that in the equation, we can solve for t.

  0 = 192 -16t^2

  0 = 12 -t^2 . . . . . . divide by 16

  t^2 = 12 . . . . . . . . add t^2

  t = √12 = 2√3 ≈ 3.464 . . . . take the square root

It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.

5 0
4 years ago
B=a+3 table of values
Lubov Fominskaja [6]
I hope this helps :)

6 0
3 years ago
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