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Natasha2012 [34]
3 years ago
11

What does (1.5,67.5) represent

Mathematics
1 answer:
sp2606 [1]3 years ago
5 0
I think it represent the a point on a graph
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1. 2(4x - 3) - 8 = 4 + 2x<br> Can sb help slove this using PEMDAS ?
velikii [3]

Answer:

x=3

Step-by-step explanation:

1) get rid of the parenthesis by distributing the 2. You will get 8x-6-8=4+2x

2) Now combine like term on each side of the equal sign. You will get 8x-14=4+2x

3) Move the 14 to the right side of the equation making it +14 and move your 2x to the left side of the equation making it -2x. You will get 8x-2x=4=+14

4) calculate each side. You will get 6x=18

5) Divide both sides. You will get x=3

4 0
4 years ago
Find the range of possible values for x
marishachu [46]

\\ \rm\longmapsto x-5=41

\\ \rm\longmapsto x=41+5

\\ \rm\longmapsto x=46

Hence

\\ \rm\longmapsto 45

6 0
3 years ago
Jon has to choose which variable to solve for in order to be able to do the problem below in the most efficient manner.
yuradex [85]

The most efficient way to solve this problem is isolating the y in the first equation because:

6x + 3y = 27

3y = 27 - 6x

y = 9 - 2x

Since all the numbers have a common factor of 3, it can be easily simplified/reduce.

If you used any other variable, you would have gotten a fraction.

Now that you found y, you can substitute it into the other equation to solve for x.  

ANYWAYS, your answer is A

7 0
4 years ago
Read 2 more answers
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
Is 3/17 a rational number
makkiz [27]

Answer:

no

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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