Ask question

Ask question

All categories

3 years ago

9

A car manufacturer has a failure rate in their oil gasket of 2%. What is the probability that , of 1200 cars built, 50 will deve

lop a failure in the gasket?

2 answers:

Karo-lina-s [1.5K]3 years ago

6 0

4% hope this helps

Please give me Brainly

Keith_Richards [23]3 years ago

4 0

Answer:

4%

Step-by-step explanation:

You might be interested in

An electronics retailer receives a shipment of 6,000CDs to distribute to its stores. A quality control manager inspects a random

Alex17521 [72]

Answer: 300

Step-by-step explanation:

Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.

i.e, Total CD's he has now = 6,000

Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.

Then , the proportion of defective( D) CD's = $\dfrac{D}{S}=\dfrac{2}{40}=0.05$

Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)

= 6000 x 0.05

=300

Hence, the number of CDs in the shipment are likely to be defective =300

8 0

3 years ago

Read 2 more answers

54 blue marbles 24 red marbles and 18 yellow marbles arranged in equal groups

vampirchik [111]

Divide each by their GCF

4 0

3 years ago

Read 2 more answers

What is the value of 2y- 6 if y = 12

Likurg_2 [28]

Answer:19

Step-by-step explanation:

The answer is 19 because you need to do 12*2 and then subtract 6. 24-6=19

3 0

3 years ago

Read 2 more answers

Divide 110 g of salt in ratio 5 : 8 : 9; what is the result ?

vekshin1

110grams÷22 =5

5+8+ 9 =22

5 x5=25

5x8=40

5x9=45

The ratio is 25:40:45

5 0

3 years ago

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago