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DaniilM [7]
3 years ago
15

Drag each equation to show if it could be a correct first step to solving the equation

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

3 + 4x = 36----->No

(4.3)+(4 . x)= 36------>Yes

4(3 + x)= 144--------->No

3+ x = 9-------> Yes

12 + x = 36------>No

12 + 4x = 36------->Yes

Step-by-step explanation:

The given equation is

4(3 + x) = 36

A correct first step is to expand the LHS to get:

12 + 4x = 36

Or to divide through by 4 to get:

3 + x = 9

Or just distribute to get:

4 \cdot 3 + 4 \cdot \: x = 36

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rewona [7]
You have to make it into a subtraction problem. 82-58=24

5 0
3 years ago
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A block of concrete is 1m long, 50cm wild and 4cm thick. 1.calculate the volume of the block in cm3 .2.if 1cm has a mass of 2.7g
Nonamiya [84]

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Answer:

  • 20,000 cm³
  • 54 kg

Step-by-step explanation:

1 m is 100 cm, so the volume is ...

  V = LWH

  V = (100 cm)(50 cm)(4 cm) = 20,000 cm³ . . . volume

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The mass is ...

  (20,000 cm³)(2.7 g/cm³) = 54,000 g = 54 kg

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7 0
3 years ago
The parabola x = y² - 9 opens:
irinina [24]
This is what it looks like. It opens to the right.

8 0
3 years ago
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The number 66 is increased to 72. What is the percentage by which the number was increased, to the nearest tenth of a percent?
Lunna [17]

Answer:

The increase is 9.1%

Step-by-step explanation:

<u>Step 1:  Make an equation </u>

66 * x = 72

66x = 72

<u>Step 2:  Divide both sides by 66 </u>

66x / 66 = 72 / 66

x = 1.09090

<u>Step 3:  Find the increased </u>

1 - 1.09090

0.091 * 100

9.1%

Answer:  The increase is 9.1%

6 0
3 years ago
Find the area of the shaded region in square units. Show your reasoning.
motikmotik

Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side l, so, the area unit is l^2

the diagonal's square is l\sqrt{2}

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2

CALCULATION OF MAIN SQUARE AREA

A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2

TOTAL AREA

A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2

3 0
3 years ago
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