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Aleks [24]
2 years ago
9

Patrick is constructing the circumscribed circle for △RST.

Mathematics
2 answers:
Liula [17]2 years ago
8 0
To me, the answer would be the option A :
 <span>Construct the perpendicular bisector of ST¯¯¯¯¯ .

Hope this helps !

Photon
</span>
castortr0y [4]2 years ago
5 0
<span>You need to construct the two perpendicular bisectors (Any 2 of the 3 will do)
So the answer is :Construct the perpendicular bisector of ST</span>
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11 divided by 20 = .55

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Find the solution of x and y
Hunter-Best [27]

Answer:

x = 1.25, y = 1.75

Step-by-step explanation:

The smaller and larger triangles are similar triangles. (the 2 triangles have the same angles).

We know that the smaller triangle has length 8 for it's bottom side when the larger triangle has length 10. This means the scale factor between the 2 is 10 / 8 which is 1.25. Therefore by multiplying the side lengths of the smaller triangle by 1.25 we get the side lengths of the larger triangle.

5 * 1.25 = 6.25

7 * 1.25 = 8.75

However we don't want the whole side lengths we want x and y, We need to subtract 5 and 7 respectively from the lengths of the larger triangles.

Therefore the lengths must be: 6.25 - 5 = 1.25

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Therefore x and y equal 1.25 and 1.75

5 0
2 years ago
What’s the standard form for 2.45x10 to the power of -4
Elenna [48]

Answer:

0.000245

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Move the decimal to the left 4 times.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=r%5E%7B7%2F8%7D%20%2Ar%5E%7B2%2F3%7D" id="TexFormula1" title="r^{7/8} *r^{2/3}" alt="r^{7/8} *
aksik [14]

Step-by-step explanation:

{r}^{ \frac{7}{8}  +  \frac{2}{3} }

{r}^{ \frac{21 + 16}{24} }

{r}^{ \frac{37}{24} }

Hope it helps:)

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3 years ago
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