1,2,4,8 I might of missed something
Step-by-step explanation:
well,
(y - 7)² = (y - 7)(y - 7)
remember how to multiply 2 expressions ?
you have to multiply every term of one expression with every term of the other expression and sum the results all up (incl. considering their individual signs, of course).
so, when we do the multiplication, we get
(y - 7)(y - 7) = y×y - 7×y - 7×y + (-7)×(-7) =
= y² - 14y + 49
and that is clearly different to y² - 49
FYI
y² - 49 is the result of
(y - 7)(y + 7)
because
y×y + 7×y - 7×y + (-7)(7) = y² - 49
Statement 3 and 4 are true as Figures 1 and 2 are not congruent and Figures 1 and 3 are not congruent
<h3>What are Congruent Figures ?</h3>
The figures that are similar in shape and size or can be mapped into one another , such figures are called Congruent Figures.
The graph has been plotted on the basis of given data.
The plot can be seen in the graph attached with the answer.
The statements that are true according to the given data is
Statement 3 and 4 are true as
Figures 1 and 2 are not congruent because figure 1 cannot be mapped onto figure 2 using a sequence of rigid transformations.
Figures 1 and 3 are not congruent because figure 1 cannot be mapped onto figure 3 using a sequence of rigid transformations.
To know more about Congruent Figures
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ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work
EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same
For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y
For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4
Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.
Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the
x²y = -4 ... (I)
Condition 2: Real parts are the same
x² + y = -3 ... (II)
We have a system of equations since both conditions must be satisfied
x²y = -4 ... (I)
x² + y = -3 ... (II)
We can rearrange equation (II) so that we have
y = -3 - x² ... (II)
Substituting into equation (I)
x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0
Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.
Solve for y:
y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4
So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:
-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i
x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i
They result in conjugates
<h3>Given</h3>
... f(x) = x² -4x +1
<h3>Find</h3>
... a) f(-8)
... b) f(x+9)
... c) f(-x)
<h3>Solution</h3>
In each case, put the function argument where x is, then simplify.
a) f(-8) = (-8)² -4(-8) +1 = 64 +32 + 1 = 97
b) f(x+9) = (x+9)² -4(x+9) +1
... = x² +18x +81 -4x -36 +1
... f(x+9) = x² +14x +46
c) f(-x) = (-x)² -4(-x) +1
... f(-x) = x² +4x +1
