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4 years ago

10

Answer the questions attached:

2 answers:

sesenic [268]4 years ago

8 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>

arlik [135]4 years ago

5 0

1. I'm not completely sure, but these angles seem to be complementary, meaning they add up to 90°. Since 75° + x = 90°, x = 15°.

2. These lines seem to be parallel. ∠4 ≅ ∠1 because they are vertical angles, ∠5 ≅ ∠1 because they are corresponding angles, and because ∠8 ≅ ∠4 (corresponding angles), ∠8 ≅ ∠1 as well. The final answer is ∠4, ∠5, and ∠8. Hope this helps!

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PLEASE HELP WITH ALGEBRA!!!

ExtremeBDS [4]

Answer: aₙ = 3 + 4ⁿ⁻¹

So the formula would be:

<u>aₙ = 3 + 4ⁿ⁻¹</u>

Where a₁ = 3

Common Ratio (r) = 4

And n = the term number that needs to be found out

Step-by-step explanation:

<u>Let's check if the answer is right:</u>

To find the 1st number in the term we can substitute 1 in for n in the equation:

a₁ = 3 + 4¹⁻¹

a₁ = 3 + 4⁰

a₁ = 3 + 1

a₁ = 4

And if going back and checking the first number in the sequence given is indeed 4, therefore this equation is correct

Hope this helps!

7 0

3 years ago

Suppose x, y and z are integers. Prove that, if 3x−y + 5z is even, then at least one of x, y or z is even.

Elden [556K]

Given:

x, y and z are integers.

To prove:

If $3x-y+5z$ is even, then at least one of x, y or z is even.

Solution:

We know that,

Product of two odd integers is always odd. ...(i)

Difference of two odd integers is always even. ...(ii)

Sum of an even integer and an odd integer is odd. ...(iii)

Let as assume x, y and z all are odd, then $3x-y+5z$ is even.

$3x$ is always odd. [Using (i)]

$5z$ is always odd. [Using (i)]

$3x-y$ is always even. [Using (ii)]

$(3x-y)+5z$ is always odd. [Using (iii)]

$3x-y+5z$ is always odd.

So, out assumption is incorrect.

Thus, at least one of x, y or z is even.

Hence proved.

4 0

3 years ago

Over what interval is the function nonlinear?

inna [77]

Answer:

Step-by-step explanation:

3rd one

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3 years ago

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saw5 [17]

Add all of them and divide by 5 :)

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3 years ago

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1/(cot^2 (x)) - 1/(cos^2 (x))

Airida [17]

Step-by-step explanation:

1 is your answer its law of trig identises

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3 years ago

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