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Alexxandr [17]
3 years ago
9

Is 3/6 greater than 0/6

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0
Yes 3/6 is greater than 0/6.
0/6 is equal to 0
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Will the product be less than or greater than the first factor? 4/9 x 3/8
Veronika [31]
It will be less than the first factor.
7 0
3 years ago
Ronny, Celina, Jack, and Michelle together placed a total of 20 brownies on a tray. Ronny placed 0.15 of the brownies, Celina pl
Marat540 [252]
To answer the question above, evaluate the number of cookies each of them placed on a tray. The calculations are shown below,
 
Ronny              C1 = 0.15 x 20 = 3
Celina              C2 = 3
Jack                 C3 = 0.30 x 20 = 6
Michelle           C4 = 20 - (3 + 3 + 6) = 8

From the calculation above, <em>Michelle</em> placed the most number of brownies on the tray. 

3 0
3 years ago
Read 2 more answers
Help please (will chose brainliest).
lara [203]
Answers with Explanation.


i. If we raise a number to an exponent of 1, we get the same number.

{10}^{1}  = 10

ii. If we raise 10 to an exponent of 2, it means we multiply 10 by itself two times.

{10}^{2}  = 10 \times 10 = 100

iii. If we raise 10 to an exponent of 3, it means we multiply 10 by itself three times.



{10}^{3}  = 10 \times  {10}^{2}  = 10 \times 100 = 1000

iv. If we raise 10 to an exponent of 4, it means we multiply 10 by itself four times.


{10}^{4}  =  10 \times {10}^{3} = 10 \times 1000 =  10000

v. If we raise 10 to an exponent of 5, it means we multiply 10 by itself five times.



{10}^{5}  = 10 \times  {10}^{4}  = 10 \times 10000 = 100000

{10}^{5}  = 100000

vi. Recall that,

{a}^{ - m}  =  \frac{1}{ {a}^{m} }
We apply this law of exponents to obtain,

{10}^{ - 2}  =  \frac{1}{{10}^{2} }  =  \frac{1}{100}

vii. We apply
{a}^{ - m}  =  \frac{1}{ {a}^{m} }
again to obtain,


{10}^{ - 3}  =  \frac{1}{ {10}^{3} }  =  \frac{1}{1000}





5 0
3 years ago
simplify the following polynomial expression. <img src="https://tex.z-dn.net/?f=%285x%5E%7B3%7D%20%2B4x%5E%7B2%7D%20%2B6x-3%29%2
FrozenT [24]
Here is the answer hope it helps

7 0
3 years ago
If the 1st and 10th terms of geometric sequence are 4 and 100, find the nth term of the sequence
Masja [62]

a = 4 first term, r = ?, T10 = 100.

Tn = ar^n - 1 formula for g.p

T10 = 4r^ 10 - 1

100 = 4r^9

Divide both side by 4

100/4 = 4/4r^9

25 = r^9 take the 9th root of both side

9√25 = 9√r^9

r = 9√25

To find the nth term

Since Tn = ar^n - 1

7 0
3 years ago
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