All categories

3 years ago

Below is a list of substances. Some are mixtures and some are not. Select all of the substances which are homogeneous.

Chemistry

1 answer:

Papessa [141]3 years ago

6 0

B the atmosphere

D. gasoline

C. a carbonated soft drink (without bubbles)

You might be interested in

The theater student talks about a type of theater from Japan called ___________.

TiliK225 [7]

I think the correct answer would be Kabuki. It is a Japanese traditional form of theater that is characterized by the heavy make-up worn by the performers. It started during the Edo Period. It is one of the major classical theater in Japan.

8 0

3 years ago

Niven wants to calculate the mass of mgo that is produced by burning of 28.0g of mg. What is the first step in nivens calculatio

babymother [125]

Answer: -

The experiment Niven is doing is burning of Mg.

The first step would be finding the molar mass of MgO

Atomic mass of Mg = 24 g

Atomic mass of Oxygen = 16 g

Molar mass of MgO = 24 x 1 + 16 x 1 = 40 g

The balanced chemical equation for this reaction is

2 Mg + O2 -- > 2MgO

From the balanced equation we see that

2 Mg gives 2 MgO

2 x24 g of Mg O gives 2 x 40 g of MgO.

28g of MgO gives $\frac{2 x 40 gram x 28 gram }{2 x 24 gram}$

= 46.66 g of MgO.

8 0

3 years ago

Read 2 more answers

A box of paper clips weighs 1.1 kg. If each paper clip weighs 0.88 grams, how many paper clips are in the box? (Hint: 1 kg = 100

PolarNik [594]

1.1kg = 1100g
If each paper clip is 0.88g : 1100 / 0.88 = 1250
1250 paper clips in the box

5 0

3 years ago

Read 2 more answers

It has been suggested that the surface melting of ice plays a role in enabling speed skaters to achieve peak performance. Carry

Fittoniya [83]

Answer:

a) Pf = 689.4 bar

b) P = 226.6 bar

c) T = 269.99 K

Explanation:

The molar volume of ice is equal to:

Vi = m/p = (18.02x10^-3 kg H2O/1 mol H2O)*(1 m^3/920 kg) = 1.96x10^-5 m^3 mol^-1

The molar volume of liquid water is equal to:

Vl = (18.02x10^-3 kg/1 mol)*(1 m^3/997 kg) = 1.8x10^-5 m^3 mol^-1

The change in volume is equal to:

ΔVchange = Vi-Vl = 1.96x10^-5 - 1.8x10^-5 = 1.5x10^-6 m^3 mol^-1

using the Clapeyron equation:

Pf = Pi + ((ΔHf*ΔT)/(ΔVf*Ti)) = 1.013x10^5 Pa + ((6010 J mol^-1 * 4.7 K)/(1.5x10^-6 * 273.15 K)) = 6.89x10^7 Pa = 689.4 bar

For the pressure we will use the equation:

P = (m*g)/A, where m is the mass, g is the acceleration of gravity and A is the area. Replacing values:

P = (79 kg * 9.81 m s^-2)/(1.9x10^-4 m * 0.18 m) = 2.26x10^7 Pa = 226.6 bar

From Clapeyron´s expression we need to clear ΔT:

ΔT = ((Pf-Pi)*ΔV*Ti)/ΔHf = ((2.26x10^7 - 6.89x10^7)*1.5x10^-6*273.15)/6010 = -3.16 K

you can evaluate the new melting point of ice:

T = Ti + ΔT = 273.15 K - 3.16 K = 269.99 K

4 0

3 years ago

When do Metallic bonds form?

Vanyuwa [196]

Metallic bonds<span>, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize</span>

3 0

3 years ago