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3 years ago

X/7 > -2. Solve and graph. Help.

Mathematics

1 answer:

ikadub [295]3 years ago

8 0

This is the answer hope i helped

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What is the remainder of 3,368,008 divided by 5574

zheka24 [161]

The answer is 604.235378543

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3 years ago

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The formula for the volume of a sphere is v= 4/3 3.14rWhat is the formula solved for r?

prohojiy [21]

Answer:

$r = \frac{3}{4\pi}V$

Step-by-step explanation:

First, the formula for the volume of a sphere is:

$V = \frac{4}{3}\pi r^3$

$\frac{3}{4}V = \pi r^3$

$\frac{3}{4}V\frac{1}{\pi} = r^3$

$r^3 = \frac{3}{4\pi}V$

$r = \sqrt[\leftroot{-2}\uproot{2}3]{\frac{3}{4\pi}V}$

If there is any steps you are unsure of, feel free to ask in the comments.

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3 years ago

Sign numbers, ratios & Proportion (+10) + (+6) = ?

Viefleur [7K]

Answer:

Step-by-step explanation:

Putting a + in front of a number indicates that the number is positive. so we are just going to add it up.

10+6=16

10:6=5:3

Hope it helps:)

7 0

4 years ago

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Two burgers and one hotdog cost $4.82. At the same price ,one burger and two hotdogs cost $3.70. How much does a hotdog cost?

STatiana [176]

Hello!

Let's use 'x' to represent the cost of the burger, and 'y' to represent the cost of the hotdog.

2x + y = 482

× + 2y = 370

2x + 47 = 740

-3y = -258

y = 86 cents

2x + 86 = 482

2x = 396

x = 198

A burger costs $1.98 and a hot dog costs $.86

I hope this didn't confuse you, I'm not very good at explaining!

8 0

3 years ago

The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser

Liono4ka [1.6K]

The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

$z-score= \frac{X-Mean}{Standard Deviation}$
$z-score= \frac{405.5-402.7}{8.8} =0.32$

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

$P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)$

from the z-table, the reading $P(Z\ \textless \ 0.32)$ gives 0.6255

hence,
$P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475$

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0

3 years ago