Hello there!
Knowing that the vertex form of the quadratic equation is
y=a(x-h)^2+k where (h,k) represents the vertex, and the a value represents the leading coefficient of the quadratic equation in standard form, first plug in your known values (your given coordinate point can be plugged into the x and y values, and your given vertex can be plugged into h and k):
-4=a(0-10)^2-9
Because your a value is still unknown, you can use your given values in the equation to solve for a:
-4=a(-10)^2-9
-4=100a-9
100a=5
a=1/20
Now that you have your a value, you can plug it into your vertex form as well as your vertex values to get that your equation in vertex form is:
y=1/20(x-10)^2-9
Answer:
16*64=1024 4*256
Step-by-step explanation:
Answer:
18,500 , 1 , 1.03
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
f(t) =18,500(1.03)^t
1st blank:
19,055
1.03
3
18,500
2nd blank:
t years
2 years
3 years
1 year
3rd blank:
19,055
3
18,500
1.03
My answer:
Given that: f(t) =18,500*
1st blank:
Initial value when t = 0, so we have:
f(0) =18,500*
So we choose D for 1st blank
2nd and 3rd blank:
Because it's an exponential function f(t) =18,500* , with every value of t increment f(t) increase by a factor of 1.03 . So Every 1 year the number of students who enroll at the university increases by a factor of 1.03
=> 2nd blank: 1
=> 3rd blank: 1.03
Hope it will find you well.
Answer:
4
Step-by-step explanation:
