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sashaice [31]
3 years ago
15

Solve the equation 3/y = 4/5

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0

Answer:

15/4

Step-by-step explanation:

3/y=4/5

3=4/5(y)

3(5)=4y

15=4y

15/4=y

netineya [11]3 years ago
4 0

Step-by-step explanation:

<u>Step 1:  Cross Multiply</u>

\frac{3}{y} = \frac{4}{5}

5(3) = 4(y)

15 = 4y

<u>Step 2:  Divide both sides by 4</u>

15 / 4 = 4y / 4

3.75 = y

Answer:  y = 3.75

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balandron [24]

Answer:

y=x-1

Step-by-step explanation:

8 0
3 years ago
write the slope - intercept equation of the line that passes through the point (6, "-1)" and has a slope of "-1/3"
TEA [102]

Answer:

y = - \frac{1}{3} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{1}{3} , then

y = - \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, - 1 ) into the partial equation

- 1 = - 2 + c ⇒ c = - 1 + 2 = 1

y = - \frac{1}{3} x + 1 ← equation of line

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3 years ago
Given the inequality below:<br><br> 3x-y&gt;4<br><br> Which is the graph of the solution set?
OLga [1]

Answer:

A shaded region below a dashed line (y <3x-4)

Step-by-step explanation:

For linear inequalities, we have shaded regions below or above a dashed or solid or continuous line represented by an inequality.

Their graphs are called region graphs. Those regions are only enclosed ones if before the sign of inequality it is included both variables. Like x²+y²<1, |x+y|<1, etc.

In this case what we have here is an open region, as the graph below shows.

3x-y>4 =-y>4-3x∴y<3x-4

Setting a value for x

3x-4=0

3x=4

3x/3=4/3

x=4/3 (slope)

(4/3,0)

6 0
3 years ago
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pychu [463]
What’s the question?
5 0
3 years ago
A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish
Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or \frac{x}{y}=\frac{333}{444}

⇒ \frac{x}{y}=\frac{3}{4}

⇒ y = \frac{4x}{3} --------(1)

Similarly x' : y' = 333 : 444

⇒ \frac{x'}{y'}=\frac{333}{444}

⇒ \frac{x'}{y'}=\frac{3}{4}

⇒ x' = \frac{3y'}{4} ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

\frac{x+y}{x'+y'}=\frac{464646}{555}

Now we replace the values of x and y' from equation (1) and equation (2)

\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}

\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}

\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}

\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}

\frac{x}{y'}=\frac{232323}{370}

\frac{y'}{x}=\frac{370}{232323}

\frac{y'}{x}=\frac{10}{6279}

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0
3 years ago
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