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3 years ago

The number of points scored by Reuben in the first five basketball games of a season are shown below.

Mathematics

1 answer:

jolli1 [7]3 years ago

8 0

Answer:

The correct option is (D).

Step-by-step explanation:

The data for the number of points scored by Reuben in the first five basketball games of a season are:

A = {23, 15, 28, 19, 25}

And the data for the number of points scored by Reuben in the next five games is:

B = {23, 30, 15, 22, 26}

For the first data there are only 5 observations to draw conclusions about the spread of the data and the peak of the distribution curve.

But after the next five games played by Reuben, there are 10 observations to draw conclusions.

The spread of the data is dependent upon the sample size.

Larger the sample size the smaller is the spread. And hence the distribution curve will be more peaked.

And smaller the sample size the larger is the spread. And hence the distribution curve will be less peaked.

So, after the next five games the distribution of Reuben's score would become more peaked and less widely spread.

The correct option is (D).

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A fountain, 3 ft in diameter, sits in the center os a circular duck pond. The pond measures 3 ft from the fountain to its edge.

umka2103 [35]

Answer:

$56.55\ ft^2$

Step-by-step explanation:

We know that the diameter of the fountain is 3 feet and that it is in the center of the pond.

We know that the area of a circumference is:

$\pi(r)^2$

where r is the radius of the circumference.

further

d = 2r

Where d is the diameter of the circumference.

Then the radius $r_1$ of the source is 1.5 ft.

The radius $r_2$ of the pond is 1.5 + 3 = 4.5 ft

Finally the area of the pond is equal to the area of the ring that is shown in the image

$A = \pi(r_2)^2 - \pi (r_1)^2\\\\A = \pi(4.5)^2 - \pi(1.5)^2\\\\A = \pi(4.5^2 - 1.5^2)\\\\A = 18\pi = 56.55\ ft^2$

5 0

3 years ago

Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t

Kobotan [32]

The volume of the region R bounded by the x-axis is: $\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}$

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

$\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}$

here:

(x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8) from the graph, we have:

$\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}$

y = 4x

Now, our region bounded by the three lines are:

y = 0
x = 2
y = 4x

Similarly, the change in polar coordinates is:

x = rcosθ,
y = rsinθ

where;

x² + y² = r² and dA = rdrdθ

Therefore;

rsinθ = 0 i.e. r = 0 or θ = 0
rcosθ = 2 i.e. r = 2/cosθ
rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)

⇒ r = 0 to r = 2/cosθ
θ = 0 to θ = tan⁻¹ (4)

Then:

$\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}$

$\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}$

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

3 0

2 years ago

The statue of liberty is 305 feet tall from the base to the torch. The statue itself is 111 feet tall. How many feet tall is the

mr Goodwill [35]

Base height + statue height = total height

Total height = 305
statue height = 111

base height + 111 = 305
Subtract both sides by 111
base height = 194

The height of the base is 194 feet.

Have an awesome day! :)

7 0

3 years ago

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Degger [83]

Answer:

http://www.classzone.com/science_book/mls_grade6_FL/540_547.pdf

Step-by-step explanation:

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3 years ago

What is the measure of angle ABC

sertanlavr [38]