Answer: see below
<u>Step-by-step explanation:</u>
42) 11 < 3y + 2 < 20
<u> -2 </u> <u> -2 </u> <u> -2 </u>
9 < 3y < 18
<u> ÷3 </u> <u>÷3 </u> <u> ÷3 </u>
3 < y < 6
Graph: o----------o
3 6
44) 36 ≥ 1 - 5z > -21
<u> -1 </u> <u> -1 </u> <u> -1 </u>
35 ≥ -5z > -22
<u> ÷ -5 </u> ↓ <u> ÷ -5 </u> ↓ <u>÷ -5 </u>
7 ≤ z < 4.4
Graph: o------------ ·
4.4 7
46) 6b + 3 < 15 or 4b - 2 > 18
<u> -3 </u> <u> -3 </u> <u> +2 </u> <u>+2 </u>
6b < 12 4b > 20
<u> ÷6 </u> <u>÷6 </u> <u> ÷4 </u> <u>÷4 </u>
b < 2 or b > 5
Graph: ←--------o o---------→
2 5
48) 8d < -64 and 5d > 25
÷8 ÷8 ÷5 ÷5
d < -8 and d > 5
there is no number that is both less than - 8 and greater than 5
No Solution
Graph: (empty)
50) 15x > 30 and 18x < -36
<u> ÷15 </u> <u> ÷15 </u> <u>÷18 </u> <u>÷18 </u>
x > 2 and x < -2
there is no number that is both less than - 2 and greater than 2
No Solution
Graph: (empty)
Answer:
So for his mark will be in between 82 to 130 for C grade
Step-by-step explanation:
We have given that for C grade the minimum average mark should be 77 and maximum average mark should be 85
There are 6 subjects
So total minimum mark = 6×77 =462
And total maximum mark = 85×6 =510
He has five grades as 74,78,76,67,85
So sum of five grades = 74+78+76+67+85=380
Let he get x marks in 6th
So for minimum mark in 6th grade x+380 = 462
x = 462-380=82
For maximum mark x+380=510
x = 510-380 =130
So for his mark will be in between 82 to 130 for C grade
The answer to your problem is 37.
Answer:
<h2>sin B sorryonlearning</h2>
