<h3>
Answer: Choice A</h3>
Side = 5 ft, side = 15 ft, side = 3 ft
Explanation:
The two sides 5 ft and 3 ft add to 5+3 = 8 ft which is not larger than the 15 ft side. This is exactly why a triangle is not possible here.
If we want a triangle to happen, then adding any two sides must be larger than the third side.
If we want a triangle with sides a,b,c, then we need the following to be true
Refer to the triangle inequality theorem for more information.
Answer: The required solution is
Step-by-step explanation: We are given to solve the following differential equation :
Let us consider that
be an auxiliary solution of equation (i).
Then, we have
Substituting these values in equation (i), we get
![m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.](https://tex.z-dn.net/?f=m%5E2e%5E%7Bmt%7D%2B10me%5E%7Bmt%7D%2B25e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%5E2%2B10y%2B25%29e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B10m%2B25%3D0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7De%5E%7Bmt%7D%5Cneq0%5D%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B2%5Ctimes%20m%5Ctimes5%2B5%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%2B5%29%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20m%3D-5%2C-5.)
So, the general solution of the given equation is
Differentiating with respect to t, we get
According to the given conditions, we have
and
Thus, the required solution is
Answer:
Step-by-step explanation:
You didn't mark your graph but I'm assuming the point is (1,2)
You notice how the function stops at the point? x and y can not be above that point because there is no line above it.
The domain of the function means what can x possibly be.
The maximum value of x in this function is 1 because that's the x value of the point where the function ended. This means x can at most be one or x≤1. So the domain is x≤1.
The range of the function means what can y possibly be.
The maximum value of y in this function is 2 because that's the y value of the point where the function ended. This means y can at most be two or y≤2. So the range is y≤2.
