The best way to do this is to draw a picture of ΔFKL and include line segment KM that is perpendicular to FL. This creates ΔFKM which is a 45°-45°-90° triangle and ΔLKM which is a 30°-60°-90° triangle.
Find the lengths of FM and ML. Then, FM + ML = FL
<u>FM</u>
ΔFKM (45°-45°-90°): FK is the hypotenuse so FM = 
<u>ML</u>
ΔLKM (30°-60°-90°): from ΔFKM, we know that KM = 
, so KL = 
<u>FM + ML = FL</u>
= 
La longitud del arco (s) en una circunferencia, conociendo el radio (r) y el ángulo (θ) que forman los dos radios, es:
s = r∙θ
Con el ángulo en radianes
F V7 w7 :
I think that it is b sorry if I’m wrong
Answer:
Step-by-step explanation:
17.7+8.3+13.0+2090=24.805g
Answer:
Step-by-step explanation:
Hmmmmm you did not give the full equation for the original line.
However, parallel lines have identical slopes. Whatever coefficient (m) is associated with the x value, will be the slope of the parallel line when the equation is put in the form
y = mx + b
