Ask question

Ask question

All categories

3 years ago

7

The sum of two even numbers is even. the sum of 6 and another number is even. what conjecture can you make about the other numbe

r?

1 answer:

Basile [38]3 years ago

6 0

We can say that the other number is even or it is 0.

You might be interested in

Is 7^2 greater then or less than 3^4?

nevsk [136]

<h2>Answer: <em><u>Less Than</u></em></h2>

Step-by-step explanation: 7^2 = 49, but 3^4 = 81. 49 < 81

7 0

2 years ago

Read 2 more answers

PLZ ANSWER QUICK!!!

alexira [117]

Answer; c^2 = a^2 + b^2

c = 17 inches

a = 8 inches

b^2 = c^2 – a^2

b^2 = 17^2 – 8^2

b^2 = 289 – 64

b^2 = 225

b = square root of 225

b = 15 inches ≈ c.

5 0

3 years ago

2(n+5)= -2 I need the full explination

lakkis [162]

Answer:

n=-6

Step-by-step explanation:

2n + 10 = -2

2n=-12

n=-6

Hope this helps!

If not I'm sorry.

3 0

2 years ago

Read 2 more answers

The values of 60, 62, and 84 were common to both samples. The three values are identified as outliers with respect to the age-gr

postnew [5]

Answer:

Only 60 is an identified outlier

Step-by-step explanation:

Given

<u>Age group: 40 to 50</u>

$Min = 60$ $Q_1 = 70$ $Median= 73$

$Q_3 = 76$ $Max = 85$

<u>Conditions for outlier</u>

$Value > Q_3 + 1.5 * IQR$

$Value < Q_1 - 1.5 * IQR$

<em>See attachment for complete question</em>

<u>Required</u>

Which of 60, 62 and 84 is an outlier of age grout 40 to 50 years

First, calculate the IQR of group 40 to 50.

This is calculated as:

$IQR = Q_3 - Q_1$

Where:

$Q_3 = 76$ and $Q_1 = 70$

So:

$IQR = 76 - 70$

$IQR = 6$

<em>Next, is to test the outlier conditions on each value (i.e. 60, 62 and 84)</em>

<u></u>

<u>Testing 60</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$60 > 76 + 1.5 * 6$

$60 > 76 + 9$

$60 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$60 < 70 - 1.5 * 6$

$60 < 70 - 9$

$60 < 61$ --- True

<em>Because one of the conditions is true, then 60 is an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 62</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$62> 76 + 1.5 * 6$

$62 > 76 + 9$

$62 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$62 < 70 - 1.5 * 6$

$62 < 70 - 9$

$62 < 61$ --- False

<em>Because both conditions are false, then 62 is not an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 84</u>

<u>Condition 1</u>

$Value > Q_3 + 1.5 * IQR$

$84> 76 + 1.5 * 6$

$84 > 76 + 9$

$84 > 85$ --- False

<u>Condition 2</u>

$Value < Q_1 - 1.5 * IQR$

$84 < 70 - 1.5 * 6$

$84 < 70 - 9$

$84 < 61$ --- False

<em>Because both conditions are false, then 84 is not an outlier of group 40 - 50 years</em>

5 0

3 years ago

Tell whether each relationship is a function.

Serhud [2]

Answer:

3 is a function.

1 and 2 are not.

Step-by-step explanation:

1 and 2 are not functions because we can draw a vertical line which passes through more than one point on the graphs.

You cant do this on graph 3 so it is a function.

8 0

3 years ago