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3 years ago

7

The sum of two even numbers is even. the sum of 6 and another number is even. what conjecture can you make about the other numbe

r?

1 answer:

Basile [38]3 years ago

6 0

We can say that the other number is even or it is 0.

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Answer #1,3,4,5,6,and 7

Fofino [41]

Can you type the answers in plz. I can't see the pic

7 0

3 years ago

Can anyone help me, i will give brainiest.

laila [671]

Answer: ∠DOB: 48°

Step-by-step explanation:

1. we need an equation first. the sum of all angles (108°, n°, 2n°) is equal to 180°. we can depict this with the equation: 108°+2n°+n°=180°

2. now we can solve for the missing variable, n.

108°+3n°=180° → subtract both sides by → 3n°=72° → divide both sides by 3 → n=24°

3. now that we know that n=24°, we can solve the value of ∠DOB. we can see that ∠DOB is 2n° which we just plug the number we got for n into the equation. 2*24=48° meaning ∠DOB is 48°

hope this heped! ♡

7 0

2 years ago

Read 2 more answers

XLiV represents 64 true ya false

V125BC [204]

Answer:

False

Step-by-step explanation:

Given

$XLIV = 64$

Required

True or False

The above numeral can be split as follows:

$XLIV = XL + IV$

X means 10 and L means 50.

But because X (10) which is smaller comes before L (50), XL is executed as:

$XL = -10 + 50$

$XL = 40$

In Roman numerals;

$IV = 4$

Substitute 40 for XL and 4 for IV.

$XLIV = 40 + 4$

$XLIV = 44$

Hence;

<em /> $XLIV = 64$ <em> is false</em>

7 0

2 years ago

PLEASE HELP ME <br> I WILL MARK BRAINLIST!!!!

elixir [45]

Answer: A

Step-by-step explanation: The slope of perpendicular lines is opposite reciprocal. In this case the slope would be 4/3. Plug in for x and y, you get -7 for b.

y = mx +b
9 = 4/3 (12) + b
9 = 16 + b
-7 = b

Rewrite the equation --> y = 4/3x - 7

5 0

3 years ago

The probability of rolling two dice at the same time and getting a 4 with either die or the sum of the dice is 6

aleksklad [387]

Answer:

Suppose that the first die we roll comes up as a 1. The other die roll could be a 1, 2, 3, 4, 5, or 6. Now suppose that the first die is a 2. The other die roll again could be a 1, 2, 3, 4, 5, or 6. We have already found 12 potential outcomes, and have yet to exhaust all of the possibilities of the first die. But with a second dice, there will be 24 different possibilities.

Step-by-step explanation:

1 2 3 4 5 6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (<u>6, 4</u>) (6, 5) (6, 6)

4 0

3 years ago