Answer:
Step-by-step explanation:
Let's use the definition of the Laplace transform and the identity given:![\mathcal{L}[t \cos 5t]=(-1)F'(s)](https://tex.z-dn.net/?f=%5Cmathcal%7BL%7D%5Bt%20%5Ccos%205t%5D%3D%28-1%29F%27%28s%29)
with ![F(s)=\mathcal{L}[\cos 5t]](https://tex.z-dn.net/?f=F%28s%29%3D%5Cmathcal%7BL%7D%5B%5Ccos%205t%5D)
.
Now, 
. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that 
.
Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that
.
Solving for F(s) on the last equation, 
, then the Laplace transform we were searching is 
5 x 5/2 = 25/2
answer
25/2 units
we have
<u>The system of equations</u>
-------> equation 
-------> equation 
Substitute equation in equation
subtract 
both sides
Divide by 
both sides
the solution is the point 
therefore
the answer is
the solution to the system of equations is the point
Answer:
A: Not sure what A is called sorry. B is called the outliner. He could be generally better at the subject and understood it more, he could have cheated on his test. He could have simply guessed and got lucky.
B: The longer he/she spent on social media the worse their test scores became.
Step-by-step explanation:
x^2 -12 x = -28
(-12/2) ^ 2 =36
x^2 -12 x + 36 = -28 + 36
x^2 -12x + 36 = 8
(x-6)^2 = 8
take the square root of each side
x-6 = sqrt (8) x-6 = -sqrt (8)
you get a positive and a negative when taking the square root
x= 6 + sqrt (8)
x = 6 - sqrt (8)
sqrt (8) = 2 sqrt (2)
x= 6 + 2 sqrt (2)
x = 6 - 2 sqrt (2)
Answer:
x= 6 + 2 sqrt (2)
x = 6 - 2 sqrt (2)
