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3 years ago

Hey, help plz! 9r/sif r = 6 and s = 3?????

Mathematics

1 answer:

slega [8]3 years ago

3 0

Answer:

Step-by-step explanation:

9 x 6 / 3

54/3

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What is the value of the expression shown 24-52

Ahat [919]

Answer:

-28

Step-by-step explanation:

It is negative so:

52-24=28

-28

8 0

3 years ago

Write the equation of a line that passes the point (-6,9)and is perpendicular to a line that passes through the points (-2,1) an

stepladder [879]

Answer:

y = 4/3x + 1.

Step-by-step explanation:

The equation of the lines passing through (2,1) and (6,7) is:

y - 7 = (7-1)/(6- -2)(x - 6)

y - 7 = 6/8(x - 6)

y = 3/4(x - 6) + 7

y = 3/4x + 5/2.

So the line perpendicular to it has slope -1/3/4 = -4/3:

y - 9 = -4/3(x + 6)

y = -4/3 x - 8 + 9

y = 4/3x + 1.

6 0

3 years ago

36 miles per 6 gallons

stepladder [879]

6 m.p.g if that's the type of question your referring to...

4 0

3 years ago

Read 2 more answers

Suppose you walk 2 miles in 35 minutes. 4. write a proportion to find how far you would walk in an hour if you were to continue

Mrac [35]

Distance traveled in 35 minute = 2 miles.

So distance traveled in one minute = 2/35 (miles/minute)
= 0.0572 miles / minute.

So distance traveled in one hour , we can find by multiplying it from 60.Because in one hour there is 60 minute.

SO distance traveled in one hour = 0.0572 * 60
= 3.432 miles / hour.

7 0

3 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

4 0

3 years ago

Read 2 more answers