All categories

3 years ago

Please help me find the which function was graphed I’m struggling a lot with functions

Mathematics

2 answers:

lord [1]3 years ago

6 0

I think the answer is B

Advocard [28]3 years ago

3 0

Answer:

answer is B

Step-by-step explanation:

............

You might be interested in

What is the inverse of y= 3/2x -2

Mashcka [7]

Answer:

f^-1(x) = (2x + 4) / 3

Step-by-step explanation:

- switch 'y' with 'x'

x = 3/2y - 2

- solve for 'y'

x + 2 = 3/2y

- multiply each side by 2

y = (2x + 4) / 3

3 0

3 years ago

A laundry bag con tans 4 green socks,6 red socks, and 2 blue socks. Inez reaches out into the bag and randomly pulls out 2 socks

IgorC [24]

P(green sock, blue sock)= 4/10*2/9=8/90

3 0

3 years ago

The center of a circle is at (0, 0), and the radius of the circle is 3(sqrt)2

Assoli18 [71]

Answer:

Step-by-step explanation:

The equation of a circle is denoted by: $(x-h)^2+(y-k)^2=r^2$ , where (h, k) is the center and r is the radius.

Here, we see that the center is (0, 0), so h = 0 and k = 0. Also, the radius is $3\sqrt{2}$ , so r = $3\sqrt{2}$ and $r^2=(3\sqrt{2})^2=9*2=18$ .

Then we can write our equation:

$(x-0)^2+(y-0)^2=18$

$x^2+y^2=18$

The answer is B.

Hope this helps!

4 0

3 years ago

Find the volume of a hemisphere of radius 5 cm.

aksik [14]

Answer:

the volume of a hemisphere with a radius of 5 feet is 261.67 cubic feet.

Step-by-step explanation:

7 0

3 years ago

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$

$P(2>Z)=.97725$

We will use formula $P(a$ to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

$P(-1$

Upon converting 0.81859 to percentage we will get

$0.81859*100=81.859\approx 81.86$

Therefore, 81.86% of final exam score will be between 68 and 86.

3 0

3 years ago