All categories

3 years ago

What is 9147392 the Rounded nearest thousand

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer: 9,147,000

Step-by-step explanation:

You might be interested in

If:

PSYCHO15rus [73]

Take some trinomial expansions to find some useful expressions and their values.

• 2nd degree expansion

$x + y + z = 7 \\\\ \implies (x+y+z)^2 = x^2+y^2+z^2+2(xy+xz+yz) = 7^2 \\\\ \implies xy+xz+yz = \dfrac{49-33}2 = 8$

• 3rd degree expansion

$x+y+z=7 \implies (x+y+z)^3 = 7^3 \\\\ \implies \\ 243 = x^3+y^3+z^3+3(x^2y+x^2z+xy^2+y^2z+xz^2+yz^2) + 6xyz \\\\ \implies \\ x^2y+x^2z+xy^2+y^2z+xz^2+yz^2 + 2xyz = \dfrac{343 - 145}3 = 66$

• 4th degree expansion

$x+y+z=7 \implies (x+y+z)^4 = 7^4 \\\\ \implies \\ 2401 = x^4+y^4+z^4+4(x^3y+x^3z+xy^3+y^3z+xz^3+yz^3) \\\\ ~~~~~~~~~~~~+ 6(x^2y^2+x^2z^2+y^2z^2) + 12(x^2yz+xy^2z+xyz^2) \\\\ \implies \\\\ x^4+y^4+z^4 = 2401 - 4(x^3y+x^3z+xy^3+y^3z+xz^3+yz^3) \\\\ ~~~~~~~~~~~~~~~~~~~~~~- 6(x^2y^2+x^2z^2+y^2z^2) - 12(x^2yz+xy^2z+xyz^2)$

Simplify:

$x^3y+x^3z+xy^3+y^3z+xz^3+yz^3 \\\\ ~~~~ = x^2 (xy+xz) + y^2 (xy+yz) + z^2 (xz + yz) \\\\ ~~~~ = x^2 (xy+xz+yz) + y^2 (xy+xz+yz) + z^2 (xy + xz + yz) - (x^2yz + xy^2z + xyz^2) \\\\ ~~~~ = (x^2+y^2+z^2) (xy+xz+yz) - xyz (x+y+z) \\\\ ~~~~ = 264 - 7xyz$

$x^2y^2+x^2z^2+y^2z^2 \\\\ ~~~~ = xy\cdot xy + xz \cdot xz + yz \cdot yz \\\\ ~~~~ = xy(xy+xz+yz) + xz(xy+xz+yz) + yz(xy+xz+yz) - 2(x^2yz+xy^2z+xyz^2) \\\\ ~~~~ = (xy+xz+yz)^2 - 2xyz(x+y+z) \\\\ ~~~~ = 64 - 14xyz$

$x^2yz+xy^2z+xyz^2 = xyz (x + y + z) = 7xyz$

Then the equation we got from the 4th degree expansion reduces to

$x^4+y^4+z^4 = 2401 - 4(264-7xyz) - 6(64-14xyz) - 12(7xyz) \\\\ ~~~~~~~~~~~~~~~~~= 961 + 28xyz$

and all we need now is the value of $xyz$ .

In the 3rd degree expansion, we have

$x^2y+x^2z+xy^2+y^2z+xz^2+yz^2 \\\\ ~~~~ = x(xy + xz) + y(xy + yz) + z(xz + yz) \\\\ ~~~~ = x(xy+xz+yz) + y(xy+xz+yz) + z(xy+xz+yz) - 3xyz \\\\ ~~~~ = (x+y+z)(xy+xz+yz) - 3xyz \\\\ ~~~~ = 56 - 3xyz \\\\ \implies (56 - 3xyz) + 2xyz = 66 \\\\ \implies xyz = -10$

So, we end up with

$x^4+y^4+z^4 = 961 - 280 = \boxed{681}$

4 0

1 year ago

What is the solution to the system of equations? Use the substitution method. {y=−2x+5 {3x−4y=2 Enter your answer in the boxes.

Nataly_w [17]

1. You have the following equations:
<span>
y=−2x+5 (i)
3x−4y=2 (ii)

2. You must substitute the equation (i) into the equation (ii), as below:

</span>3x−4y=2
3x-4(−2x+5)=2
3x+8x-20=2
11x-20=2

3. Now, you must clear the variable "x":

11x=2+20
x=22/11
x=2

4. You have the value of "x", so you can find the value of "y". When you substitute x=2 into the equation (i), you obtain:

y=−2x+5
y=-2(2)+5
y=-4+5
y=1

5. Therefore, the answer is:

x=2
y=1

7 0

4 years ago

In the parking lot shown, the lines

jolli1 [7]

22 is the answer because I just did it

8 0

4 years ago

What is the volume of the box below ?5cm,8cm,10cm

Alecsey [184]

Answer: Hi!

To find the volume of a box (or cube), you multiply length times width times height.

In this case, you have all of the measurements, so all we have to do is multiply them together!

5cm * 8cm * 10cm = 400

So, the volume of this box is 400cm^3!

Hope this helps!

5 0

3 years ago

Need help with one and two

adoni [48]

Answer:

(1) is a function, surjective aka onto,

not bijective aka one to one.

domain is {3,6,12,14,20,22},

range is {4,15,8,11}. More elements in domain means it can't possibly be one to one.

(2) is a relation but not a function, although its inverse is a function. There are fewer elements in the domain than the range, so a function could not be onto but would have to be into or injective.

The relation you get by restricting the domain to {1,19} is a function, injective, so that the image of the domain is a proper subset of the range.

7 0

3 years ago