Addition of 6q + 1 and q + 11 is 7q + 12
<em><u>Solution:</u></em>
Given that, we have to add the given two expressions
<em><u>Given expressions are:</u></em>
6q + 1 and q + 11
We have to add both the expressions
Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11
Add the coefficients of same variable. Here "q" is present in two terms
Therefore, add 6q and q
Similarly, add the constants 1 and 11
<em><u>Thus finally addition is done as:</u></em>

Thus addition of 6q + 1 and q + 11 is 7q + 12
Answer:
The answer is 3m^2
Step-by-step explanation:
Work is shown
Answer:
2
Step-by-step explanation:
To find the slope, we use the equation
m = (y2-y1)/(x2-x1)
Since the have the points (2,-4) and (4,0)
m = (0--4)/ (4-2)
= (0+4)/(4-2)
= 4/2
=2
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Step-by-step explanation:
log(x+2)-log(x-1)=log2
log(x+2)/(x-1)=log2
=> (x+2)=2(x-1)
=>x+2 =2x-2
=> x=4