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3 years ago

12

Help me pls. not links pls

1 answer:

adelina 88 [10]3 years ago

4 0

Answer:
y = 1/2x

step-by-step explanation:
first find the y-intercept or b
it is 0
next find the slope, rise/run
it is 5/10 or 1/2x
putting those in the equation it would be
y = 1/2x
because the y-intercept is 0 you wouldn’t add it

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Pentagon with a side of 6 ft

TEA [102]

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2 years ago

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11111nata11111 [884]

Answer:

A circle of radius = 7 or diameter = 14 or circumference = 43.98 meters has an area of: 0.0001539 square kilometers (km²) 153.9 square meters (m²) 1.539 × 10 6 square centimeters (cm²)

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2 years ago

HELP PLZ PICK ONE OF THE ONES SHOWN:

defon

I am doing with Question Number 2

Let the two numbers be 'x' and 'y'.

According to the question, the product of two numbers is 14.

$x \times y=14$

So, xy=14 (Equation 1)

Now, one of the numbers is 3 ½ times the other.

So, $x = 3\frac{1}{2}\times y$

$x=\frac{7}{2}y$ (Equation 2)

Substituting the value of 'x' from equation 2 in equation 1, we get

$\frac{7}{2}y \times y = 14$

$\frac{7}{2}y^{2} = 14$

$y^{2} = 4$

So, y= 2 and -2

So, $x=\frac{14}{2}$ and $x=\frac{14}{-2}$

x=7 and -7

Numbers are 2,7 and -2,-7.

Sum of numbers 2 and 7 = 9

Sum of numbers -2 and -7 = -9.

6 0

3 years ago

What is 119 over 8 in its simplest form?

ivolga24 [154]

119/8 is already in simplest form. However, if you attempt to change it to a mixed number the correct answer would be 14 7/8 (7 over 8).

Hope I helped!

3 0

3 years ago

Solve for x write the exact answer using either base -10 or base-e logarithms

jeka57 [31]

<u>Given</u>:

The given expression is $2^{x+5}=13^{2 x}$

We need to determine the value of x using either base - 10 or base - e logarithms.

<u>Value of x:</u>

Let us determine the value of x using the base - e logarithms.

Applying the log rule that if $f(x)=g(x)$ then $\ln (f(x))=\ln (g(x))$

Thus, we get;

$\ln \left(2^{x+5}\right)=\ln \left(13^{2 x}\right)$

Applying the log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ , we get;

$(x+5) \ln (2)=2 x \ln (13)$

Expanding, we get;

$x \ln (2)+5 \ln (2)=2 x \ln (13)$

Subtracting both sides by $5 \ln (2)$ , we get;

$x \ln (2)=2 x \ln (13)-5 \ln (2)$

Subtracting both sides by $2 x \ln (13)$ , we get;

$x \ln (2)-2 x \ln (13)=-5 \ln (2)$

Taking out the common term x, we have;

$x( \ln (2)-2 \ln (13))=-5 \ln (2)$

$x=\frac{-5 \ln (2)}{\ln (2)-2 \ln (13)}$

$x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

Thus, the value of x is $x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

6 0

3 years ago