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Ivanshal [37]
3 years ago
11

The population of bacteria in a certain culture can be modeled by the function P(t)=10000(1.03)^t. Is the population of bacteria

increasing or decreasing? Explain

Mathematics
2 answers:
slega [8]3 years ago
8 0

Answer:

Increasing

Step-by-step explanation:

If the number in the parenthesis is larger 1 or larger than it is increasing, but if it is less than one, it's decreasing. This is greater than one.

ch4aika [34]3 years ago
4 0

Answer:

The population of bacteria is increasing.

Step-by-step explanation:

The function modelling the population of bacteria in the given culture is an exponential function; We have a base 1.03 and an exponent t. An exponential function is said to be increasing if the base is strictly greater than 1, this implies that the population of the bacteria is increasing as t increases from 0 to infinity.

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Inessa [10]
5= (6+4)x
5= 10x

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10   10
.5 = x                               you can use .5 or 1/2


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3 0
3 years ago
The last part of question says find temperature at 11pm
andrezito [222]

Answer:

3 deg C

Step-by-step explanation:

Start with -8 deg and add 11 deg.

-8 + 11 = 3

Answer: 3 deg C

5 0
2 years ago
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horrorfan [7]
-4 and -5
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5 0
3 years ago
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Pani-rosa [81]

Answer:

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Step-by-step explanation:

7 0
3 years ago
The temperature was 54 at 7:00 a.m. At 3:00 p.m. on the same day, the temperature was 82. What is the rate of change in temperat
vampirchik [111]

Answer:

The rate of change was 3.5 degrees / h.

Step-by-step explanation:

In order to calculate the rate of change we need to divide the variation of temperature by the variation of time. Since the time is given to us in a 12 h format (am/pm), we first need to convert it to 24 h. To do that we sum the time that is "pm" by 12, we have:

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Therefore the rate of change in temperature is:

rate = variation of temp / variation of time

rate = (temp final - temp init) / (time final - time init)

rate = (82 - 54) / (15 - 7) = 28 / 8 = 3.5 degrees / h

The rate of change was 3.5 degrees / h.

4 0
3 years ago
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