<span>You have mentioned that two of the angles of ΔKSD are
∠K=16° and ∠D=34°. So that would mean that ∠S=130°,
because∠K+∠D+∠S=180°. That's because all the angles
of any triangle must total 180°.
But you also say that ∠T=51°. But since no angle of
ΔKSD can equal 51°, neither can any angle of ΔWAT
equal to 51°. Therefore ∠T=51° is impossible!</span>
41 years old as 47 take away 6 makes 41
A) z value = (x - π) / <span>σ = 100 - 133 / 23 = -1.43
p(<= 100) = 0.0764
</span>
There are no given coordinates, so it's impossible to answer your question. I'm sorry.
