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max2010maxim [7]
3 years ago
15

-pls help will mark brainliest-

Chemistry
1 answer:
Leni [432]3 years ago
8 0

Answer:

Explanation: d

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Calculate the millimoles of solute in 1.88 L of a 0.00713 M NaCN solution. millimoles:
konstantin123 [22]

Answer:

13.4 milimoles.

Explanation:

The following data were obtained from the question:

Volume = 1.88 L

Molarity = 0.00713 M

Millimoles of NaCN =?

Next, we shall determine the number of mole NaCN in the solution. This can be obtained as follow:

Molarity = mole /Volume

Volume = 1.88 L

Molarity = 0.00713 M

Mole of NaCN =?

Molarity = mole /Volume

0.00713 = moles of NaCN /1.88

Cross multiply

Mole of NaCN = 0.00713 × 1.88

Mole of NaCN = 0.0134 mole

Finally, we shall convert 0.0134 mole to Millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

0.0134 mole = 0.0134 × 1000

0.0134 mole = 13.4 milimoles

Therefore, the millimoles of the solute, NaCN in the solution is 13.4 milimoles

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4 years ago
Zn + 2 HCl → ZnCl2 + H2
MrRissso [65]

Answer:

10.1g of H₂ are produced

Explanation:

To solve this question we need, first, to convert the mass of each reactant to moles and, using the chemical reaction, find limiting reactant. With limiting reactant we can find the moles of H2 and its mass:

<em>Moles Zn -Molar mass: 65.38g/mol-:</em>

307g * (1mol / 65.38g) = 4.696 moles

<em>Moles HCl -Molar mass: 36.46g/mol-:</em>

381g HCl * (1mol / 36.46g) = 10.45 moles

For a complete reaction of 10.45 moles of HCl are required:

10.45 moles HCl * (1mol Zn / 2mol HCl) = 5.22 moles Zn

As there are 4.696 moles of Zn, <em>Zn is the limiting reactant</em>

<em />

The moles of H₂ produced = Moles of Zn added = 4.696 moles. The mass is-Molar mass H₂ = 2.16g/mol-:

4.696 moles * (2.16g / mol) =

<h3>10.1g of H₂ are produced</h3>
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Which metallic properties are caused by atoms rolling over each other in metallic bonds?
Pani-rosa [81]

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