Answer:
13.4 milimoles.
Explanation:
The following data were obtained from the question:
Volume = 1.88 L
Molarity = 0.00713 M
Millimoles of NaCN =?
Next, we shall determine the number of mole NaCN in the solution. This can be obtained as follow:
Molarity = mole /Volume
Volume = 1.88 L
Molarity = 0.00713 M
Mole of NaCN =?
Molarity = mole /Volume
0.00713 = moles of NaCN /1.88
Cross multiply
Mole of NaCN = 0.00713 × 1.88
Mole of NaCN = 0.0134 mole
Finally, we shall convert 0.0134 mole to Millimoles. This can be obtained as follow:
1 mole = 1000 millimoles
Therefore,
0.0134 mole = 0.0134 × 1000
0.0134 mole = 13.4 milimoles
Therefore, the millimoles of the solute, NaCN in the solution is 13.4 milimoles
