The amount of heat required is calculated using the below formula
Q(heat) =M(mass) xC(specific heat capacity)x delta T (change in temperature)
change in the temperature in kelvin=(35+273)- (25 +2730= 10K
c= 2.48 j/g/k
mass= 54.0 g
Q= 54.0 g x 2.48 j/g/k x 10k = 1339.2 joules is required
It protects the alloy against rusting.
Stainless steels contain more than 10% chromium by mass, but almost no carbon. Stainless steels are durable because chromium forms an oxide that protects the steel from rusting. But stainless steel is more brittle than steels that contain more carbon.
<span>In this work the performance of gypsum plaster and wood particle in pastes and composites was investigated. Wood particles of fineness 0.42 mm and 1.20 mm were employed. Natural wood particles and the treated ones in cold or hot water (80 °C) were performed. The effects of the extractives solutions from the treatments applied to the wood particles on wood-gypsum compatibility were studied. For pastes and composites, water-to-gypsum ratio was 0.65. Wood particles-to-gypsum plaster ratios were 5%, 10% and 15%, in mass. Kinetics of temperature, mechanical performance and dynamic elasticity modulus by ultrasound measurements were applied to evaluate the gypsum plaster pastes and its composites behaviors. Results show that the extractive solutions changed the time of gypsum plaster hydration, being more sensitive to hot water treatment. The composites compressive strength increase with the wood particles pretreatment. The best result was to room temperature treatment. The same performance was found to the modulus of elasticity. Treatments have improved significantly the flexural strength. The best wood particle content was 10%. These results show the possibility of using this wood waste with an easy and simple treatment to make eco-efficient building materials.</span>
Since the Carbon C is 17.39% by mass hence the Fluorine F
is 82.61% by mass. Divide each mass % by the respective molar masses, that is:
C = 17.39 / 12 = 1.45
F = 82.61 / 19 = 4.35
Divide the two by the smaller number, so divide by 1.45
C = 1.45 / 1.45 = 1
F = 4.35 / 1.45 = 3
So the empirical formula is:
CF3
