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3 years ago

What can be created with differential weathering

1 answer:

4 0

rocks weather at different rates and in different ways. Rocks may be more or less susceptible to weathering because of such things as composition or induration, the hardening of a rock through processes like increased temperature of formation, pressure of formation or cementation of particles by precipitated minerals.

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4 years ago

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When an object is thrown, the thrower pushes the object. This causes the object to move in a

bija089 [108]

Answer:

Gains Kinetic Energy

Explanation:

Kinetic energy (KE) is the energy inserted on the object in motion. Having gained this energy enerted upon, the body maintains this kinetic energy unless its speed changes.

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3 years ago

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The free energy of formation of nitric oxide, NO, at 1000 K (roughly the temperature in an automobile engine during ignition) is

Assoli18 [71]

Answer: The value of $K_p$ for the chemical equation is $8.341\times 10^{-5}$

Explanation:

For the given chemical equation:

$N_2(g)+O_2(g)\rightarrow 2NO(g)$

To calculate the $K_p$ for given value of Gibbs free energy, we use the relation:

$\Delta G=-RT\ln K_p$

where,

$\Delta G$ = Gibbs free energy = 78 kJ/mol = 78000 J/mol (Conversion factor: 1kJ = 1000J)

R = Gas constant = $8.314J/K mol$

T = temperature = 1000 K

$K_p$ = equilibrium constant in terms of partial pressure = ?

Putting values in above equation, we get:

$78000J/mol=-(8.314J/Kmol)\times 1000K\times \ln K_p\\\\Kp=8.341\times 10^{-5}$

Hence, the value of $K_p$ for the chemical equation is $8.341\times 10^{-5}$

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4 years ago

For which of the following elements (in their normal, stable, forms) would it be correct to describe the bonding as involving a

Dvinal [7]

Answer: The correct option is e.

Explanation: In the given question it is asked to tell the element which has 'Sea of electrons' while bonding.

This means that the element should have extra electrons so that it can bond easily or this also means which element can easily donate its electron to form a bond.

Electronic configuration of Hydrogen = $1s^1$

Hydrogen cannot loose electrons easily because the electron is present in 1s sub-shell which is the closest to the nucleus and hence will be tightly bonded to it.

Electronic configuration of Helium = $1s^2$

This element will not loose electrons easily because the 1s sub-shell is fully filled and hence will not be available for bonding.

Electronic configuration of Sulfur = $3s^23p^4$

This element lacks 2 electrons from attaining stable configurations. Hence, it will gain 2 electrons rather than donating for bonding.

Electronic configuration of Iodine = $5s^25p^5$

This element lacks 1 electron to attain stable configuration. Hence, it will gain 1 electron rather than donating for bonding.

Electronic configuration of Lithium = $1s^22s^1$

This element has an extra electron in its valence shell and can be easily lost in order to form bond.

Hence, the correct option is e.

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4 years ago