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stepladder [879]
3 years ago
10

Answer me ASAP its very important like very helpme

Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

90 minutes

Step-by-step explanation:

40/1 =60/x

We would divide 60 by 40 and I got 1.5 which is one hour and a half(30).

One hour=60 minutes

A half=30minutes

60min+30min=90min

90 is the answer.

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Triangle Q R S is shown. Angle Q R S is a right angle. Angle R S Q is 30 degrees and angle S Q R is 60 degrees. The length of R
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The value of sin(30°) is: One-half ⇒ 2nd answer

Step-by-step explanation:

In a right triangle there are two acute angles, the side opposite to the right angle is called hypotenuse, and the other two sides are opposite and adjacent to the acute angles

  • sine the acute angle (sin) = opposite side to it/hypotenuse
  • cosine the acute angle (cos) = adjacent side to it/hypotenuse
  • Tangent the acute angle (tan) = opposite side to it/adjacent side to it

In Δ QRS:

∵ m∠QRS = 90°

∵ SQ is opposite to ∠QRS

∴ SQ is the hypotenuse

∵ SQ = 10 units

∴ The hypotenuse = 10

∵ m∠RSQ = 30°

- The opposite side to ∠RSQ is RQ

∵ RQ = 5 units

∴ The opposite side to the angle of 30° = 5

∵ sin(30°) = opposite side to 30°/hypotenuse

∵ The opposite side to angle 30° = 5

∵ The hypotenuse = 10

∴ sin(30°) = \frac{5}{10}

∴ sin(30°) = \frac{1}{2}

The value of sin(30°) is: One-half

Learn more:

You can learn more about the trigonometry ratios in brainly.com/question/9880052

#LearnwithBrainly

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Using Pythagoras
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Step-by-step explanation:

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Answer:

1)\\\large\boxed{x=\dfrac{a+c}{b},\ if\ b\neq0}\\\\2)\\\boxed{if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number}\\\\\boxed{if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)}

Step-by-step explanation:

1)\\a-(a+b)x=(b-a)x-(c+bx)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\a-ax-bx=bx-ax-c-bx\qquad\text{cancel}\ bx\ \text{on the right side}\\\\a-ax-bx=-ax-c\qquad\text{add}\ ax\ \text{to both sides}\\\\a-bx=-c\qquad\text{subtract}\ a\ \text{from both sides}\\\\-bx=-a-c\qquad\text{divide both sides by}\ -b\neq0\\\\x=\dfrac{-a-c}{-b}\\\\x=\dfrac{a+c}{b}

2)\\2(3x-5a)+9(2a-7b)+3(5a-2x)=0\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\\\(2)(3x)+(2)(-5a)+(9)(2a)+(9)(-7b)+(3)(5a)+(3)(-2x)=0\\\\6x-10a+18a-63b+15a-6x=0\qquad\text{combine like terms}\\\\(6x-6x)+(-10a+18a+15a)-63b=0\\\\23a-63b=0\qquad\text{add}\ 63b\ \text{to both sides}\\\\23a=63b\qquad\text{divide both sides by 23}\\\\a=\dfrac{63b}{23}\\\\if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number\\\\if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)

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