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1 year ago

Calculate the distance between the points P=(-9, 1) and C=(−6, 8) in the coordinate plane.

Mathematics

1 answer:

Alekssandra [29.7K]1 year ago

6 0

Using Pythagoras
Distance between P and C = sr[(-6 - -9)^2 + (8 - 1)^2]
= sr(3^2 + 7^2)
= sr(9 + 49)
= sr(58) exactly

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The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately 0.7. What is the probability

victus00 [196]

Answer: 0.2401

Step-by-step explanation:

The binomial distribution formula is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.

Number of trials : n= 4

Now, the required probability will be :

$P(x=4)=^4C_4(0.7)^4(1-0.7)^{4-4}\\\\=(1)(0.7)^4(1)=0.2401$

Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401

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2 years ago

Please help me I’ve been struggling

Shalnov [3]

Your answer will be 5.
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2 years ago

Write a quotient of integers that is not a real number

ivanzaharov [21]

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According to the question;

We are required to write a quotient of integers which is not real number.

In essence, by considering integers, 40 and 22; we have;

40/22

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Read more on non-real numbers;

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2 years ago

Read 2 more answers

The probability that a call received by a certain switchboard will be a wrong number is 0.02. Use the Poisson distribution to ap

MAXImum [283]

Answer:

0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

The probability that a call received by a certain switchboard will be a wrong number is 0.02.

150 calls. So:

$\mu = 150*0.02 = 3$

Use the Poisson distribution to approximate the probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Either there are less than two calls from wrong numbers, or there are at least two calls from wrong numbers. The sum of the probabilities of these events is 1. So

$P(X < 2) + P(X \geq 2) = 1$

We want to find $P(X \geq 2)$ . So

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

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$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0498 + 0.1494 = 0.1992$

Then

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1992 = 0.2008$

0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

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3 years ago

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2 years ago