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aleksandr82 [10.1K]
2 years ago
5

Calculate the distance between the points P=(-9, 1) and C=(−6, 8) in the coordinate plane.

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
6 0
Using Pythagoras
Distance between P and C = sr[(-6 - -9)^2 + (8 - 1)^2]
= sr(3^2 + 7^2)
= sr(9 + 49)
= sr(58) exactly
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I’m kinda confused. Can someone help.
horsena [70]

Answer:

PQ = PM\cos MPQ + MQ\cos MQP=2PM\cos MQP

Step-by-step explanation:

given MQR = 60, PQR = 75

MQP = 75 -60= 15QR = ((18(1+\cos 30))^{2}-(2\cos 15)^{2})^{\frac{1}{2}}

WE KNOW THAT MQR +QRM +QMR = 180

MPQ = MQP AS ANGLE OPPOSITE TO EQUAL SIDES ARE EQUAL

THEREFORE QMR = 90 - 60 = 30

therefore PQM = 75 - 60 = 15

PM = PQ because M is the mid point

therefore PR = PM + MQ\cos QMR

                PR = 18(1+\cos 30)

QR = (PR^{2}-PQ^{2}))^{\frac{1}{2}}

PQ = PM\cos MPQ + MQ\cos MQP=2PM\cos MQP

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