Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
#18
Answer C
4*7 = 28 which is the most closest one to 27.8
#19
perimeter = 2(L+W)
175.33 feet = 2103. 96 in
2 ( 2103.96 +48)
2 * 2151.96
4303.92 inches
#20
L*W = A
2103.96 * 48
100990.08 inch^2
to lazy to do the rest sorry
Answer:
cxa=t cause you are mulltipling to find the total cost
Answer:
i cant entirely see the image well, but the<u> y intercept</u> should be the line that passes through the line on the graph that goes <u>up and down</u>
<u>Step-by-step explanation:</u>
i hope this helps :))
The decimal approximations are:
The square root of 5 is about 2.2
The square root of 8 is about 2.8
pi is about 3.14
2 square roots of 5 are about 4.4
The numbers are also placed in order from least to greatest.
