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MissTica
3 years ago
10

Which values are equivalent to the fraction below? 6^7/6^5

Mathematics
1 answer:
Helen [10]3 years ago
4 0

Answer:

36

Step-by-step explanation:

Because the bases are the same we can just subtract the exponents to get us 6² or 36.

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Express the given expanded numeral as a Hindu-Arabic numeral. (8x102) +(4x10)(2x1)
Marysya12 [62]

Answer:

The Hindu-Arabic numeral form of the given expanded numeral is 842.

Step-by-step explanation:

The given expanded numeral is

(8\times 10^2)+(4\times 10)+(2\times 1)

We need to express the given expanded numeral as a Hindu-Arabic numeral.

According to Hindu-Arabic numeral the given expanded numeral is written as

(8\times 10^2)+(4\times 10)+(2\times 1)=(8\times 100)+(4\times 10)+(2\times 1)

On simplification we get,

(8\times 10^2)+(4\times 10)+(2\times 1)=(800)+(40)+(2)

(8\times 10^2)+(4\times 10)+(2\times 1)=842

Therefore the Hindu-Arabic numeral form of the given expanded numeral is 842.

5 0
4 years ago
No links help pls like now
klasskru [66]
I think it’s maybe Top right try that
3 0
3 years ago
Find the inverse of the function. f(x) = the cube root of quantity x divided by seven. - 9
elena-14-01-66 [18.8K]
To solve

replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

so
I'm not sure if it is
f(x)=\sqrt[3]{\frac{x}{7}}-9 or
f(x)=\sqrt[3]{\frac{x}{7}-9}


first one
f(x)=\sqrt[3]{\frac{x}{7}}-9
replace f(x) with y
y=\sqrt[3]{\frac{x}{7}}-9
switch x and y
x=\sqrt[3]{\frac{y}{7}}-9
solve for y
x+9=\sqrt[3]{\frac{y}{7}}
(x+9)^3=\frac{y}{7}
7(x+9)^3=y
replace y  with f⁻¹(x)
f^{-1}(x)=7(x+9)^3

2nd one
f(x)=\sqrt[3]{\frac{x}{7}-9}
replce f(x) with y
y=\sqrt[3]{\frac{x}{7}-9}
switch x and y
x=\sqrt[3]{\frac{y}{7}-9}
solve for y
x^3=\frac{y}{7}-9
x^3+9=\frac{y}{7}
7(x^3+9)=y
replace y  with f⁻¹(x)
f^{-1}(x)=7(x^3+9)



if you meant f(x)=\sqrt[3]{\frac{x}{7}}-9  then the inverse is f^{-1}(x)=7(x+9)^3

if you meant f(x)=\sqrt[3]{\frac{x}{7}-9}  then the inverse is f^{-1}(x)=7(x^3+9)

7 0
3 years ago
I'm doing a density board game and I need questions. so can you please put density related questions. whoever puts the most impo
Kryger [21]
He helped live the world a save place
7 0
3 years ago
Read 2 more answers
Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P
Gekata [30.6K]

Answer:

The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

3x+100= 5x

solve for x

5x-3x=100\\2x=100\\x=50\ min

therefore

The number of minutes in a month must be equal to 50 minutes

5 0
4 years ago
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